QUESTION 13:
What type of exception is thrown if the user enters a 0 for the divisor?
The catch{} blocks are in a correct order,
because ArithmeticException is not
an ancestor nor a descendant of InputMismatchException.
Reversing the order of the two blocks would also work.
In the example program,
the try{} block
might throw
a NumberFormatException,
or
an ArithmeticException.
public static void main ( String[] a )
. . . .
try
{
System.out.print("Enter the numerator: ");
num = scan.nextInt();
System.out.print("Enter the divisor : ");
div = scan.nextInt();
System.out.println( num + " / " + div + " is " + (num/div) + " rem " + (num%div) );
}
catch (InputMismatchException ex )
{
. . .
}
catch (ArithmeticException ex )
{
. . .
}
}
A NumberFormatException might occur in either call to
nextInt().
The first catch{} block is for this type of exception.
An ArithmeticException might occur if the user enters
data that can't be used in an integer division.
The second a catch{} block is for this type of exception.
What type of exception is thrown if the user enters a 0 for the divisor?