{"id":2323,"date":"2017-01-29T12:56:19","date_gmt":"2017-01-29T20:56:19","guid":{"rendered":"http:\/\/www.wou.edu\/chemistry\/?page_id=2323"},"modified":"2017-04-17T11:26:08","modified_gmt":"2017-04-17T18:26:08","slug":"ch105-chapter-7","status":"publish","type":"page","link":"https:\/\/wou.edu\/chemistry\/courses\/online-chemistry-textbooks\/ch105-consumer-chemistry\/ch105-chapter-7\/","title":{"rendered":"CH105: Chapter 7 &#8211; Alkanes and Halogenated Hydrocarbons"},"content":{"rendered":"<h2 id=\"topch7\"><span style=\"color: #000000;\"><strong>Chapter 7: Alkanes and Halogenated Hydrocarbons<\/strong><\/span><\/h2>\n<p><span style=\"color: #000000;\">This text is published under creative commons licensing, for referencing and adaptation, please click<\/span> <span><a href=\"https:\/\/wou.edu\/chemistry\/courses\/online-chemistry-textbooks\/ch105-consumer-chemistry\/\"><strong><em>here. <\/em><\/strong><\/a><\/span><\/p>\n<h4><a href=\"#opening\"><span style=\"color: #000000;\"><strong>Opening Essay<\/strong><\/span><\/a><\/h4>\n<h3><a href=\"#recognition\"><strong><span style=\"color: #ff0000;\"><span class=\"title-prefix\">7.1<\/span> Recognition of Organic Structures<\/span><\/strong><\/a><\/h3>\n<h3><a href=\"#introalkanes\"><strong><span style=\"color: #ff0000;\"><span class=\"title-prefix\">7.2<\/span> Introduction to Alkanes<\/span><\/strong><\/a><\/h3>\n<h4><a href=\"#straight\"><span style=\"color: #000000;\"><strong>Straight Chain Alkanes<\/strong><\/span><\/a><\/h4>\n<h4><a href=\"#branched\"><span style=\"color: #000000;\"><strong>Branched Chain Alkanes<\/strong><\/span><\/a><\/h4>\n<h4><a href=\"#cycloalkanes\"><span style=\"color: #000000;\"><strong>Cycloalkanes<\/strong><\/span><\/a><\/h4>\n<h4><a href=\"#classification\"><span style=\"color: #000000;\"><strong>Classification of Carbon Bonds<\/strong><\/span><\/a><\/h4>\n<h3><a href=\"#properties\"><span style=\"color: #ff0000;\"><strong><span class=\"title-prefix\">7.3 <\/span>Properties of\u00a0Alkanes<\/strong><\/span><\/a><\/h3>\n<h4><a href=\"#meltingboiling\"><span style=\"color: #000000;\"><strong>Melting Points and Boiling Points<\/strong><\/span><\/a><\/h4>\n<h4><a href=\"#solubility\"><strong><span style=\"color: #000000;\">Solubility<\/span><\/strong><\/a><\/h4>\n<h4><a href=\"#hazards\"><strong><span style=\"color: #000000;\">Alkane Properties and Environmental Hazards: A Closer Look<\/span><\/strong><\/a><\/h4>\n<h3><a href=\"#reactivity\"><strong><span style=\"color: #ff0000;\">7.4 Chemical Reactivity of Alkanes<\/span><\/strong><\/a><\/h3>\n<h4><a href=\"#combustion\"><span style=\"color: #000000;\"><strong>Combustion Reactions<\/strong><\/span><\/a><\/h4>\n<h4><a href=\"#halogenation\"><span style=\"color: #000000;\"><strong>Halogenation Reactions (Substitution Type)<\/strong><\/span><\/a><\/h4>\n<h4><a href=\"#cracking\"><span style=\"color: #000000;\"><strong>Cracking Alkanes<\/strong><\/span><\/a><\/h4>\n<h3><a href=\"#summary7\"><span style=\"color: #ff0000;\"><strong>7.5 Chapter Summary<\/strong><\/span><\/a><\/h3>\n<h3><a href=\"#exercisesend\"><span style=\"color: #ff0000;\"><strong>7.6 End-of-Chapter Exercises<\/strong><\/span><\/a><\/h3>\n<h3><a href=\"#refs7\"><span style=\"color: #ff0000;\"><strong>7.7 References<\/strong><\/span><\/a><\/h3>\n<p>&nbsp;<\/p>\n<hr \/>\n<div class=\"callout editable block\" id=\"opening\">\n<h4 class=\"title\"><strong><span style=\"color: #000000;\">Opening Essay<\/span><\/strong><\/h4>\n<p class=\"para\" id=\"gob-ch12_p01\"><span style=\"color: #000000;\">Hydrocarbons are the simplest organic compounds, but they have interesting physiological effects. These effects depend on the size of the hydrocarbon molecules and where on or in the body they are applied. Alkanes of low molar mass\u2014those with from 1 to approximately 10 or so carbon atoms\u2014are gases or light liquids that act as anesthetics. Inhaling (\u201csniffing\u201d) these hydrocarbons in gasoline or aerosol propellants for their intoxicating effect is a major health problem that can lead to liver, kidney, or brain damage or to immediate death by asphyxiation by excluding oxygen.\u00a0\u00a0Pressurized canisters of propane and butane gas, both of which are intended for use as fuels, are\u00a0abused as inhalants.<\/span><\/p>\n<p class=\"para\"><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/petroleum-products.jpg\"><img loading=\"lazy\" decoding=\"async\" width=\"679\" height=\"446\" class=\"alignnone wp-image-2479\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/petroleum-products-1024x672.jpg\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/petroleum-products-1024x672.jpg 1024w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/petroleum-products-300x197.jpg 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/petroleum-products-768x504.jpg 768w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/petroleum-products.jpg 1920w\" sizes=\"(max-width: 679px) 100vw, 679px\" \/><\/a><\/p>\n<p class=\"para\"><span style=\"color: #000000;\"><strong>Figure 7.1. A range of petroleum-based products that can be abused as inhalants<\/strong>. Photo By:<\/span> <a href=\"https:\/\/commons.wikimedia.org\/w\/index.php?curid=22991506\">Lance Cpl. Matthew K. Hacker<\/a><\/p>\n<hr \/>\n<p class=\"para\" id=\"gob-ch12_p02\"><span style=\"color: #000000;\">Swallowed, liquid alkanes do little harm while in the stomach. In the lungs, however, they cause \u201cchemical\u201d pneumonia by dissolving fatlike molecules from cell membranes in the tiny air sacs (alveoli). The lungs become unable to expel fluids, just as in pneumonia caused by bacteria or viruses. People who swallow gasoline or other liquid alkane mixtures should not be made to vomit, as this would increase the chance of getting alkanes into the lungs. (There is no home-treatment antidote for gasoline poisoning; call a poison control center.)<\/span><\/p>\n<p class=\"para\" id=\"gob-ch12_p03\"><span style=\"color: #000000;\">Liquid alkanes with approximately 5\u201316 carbon atoms per molecule wash away natural skin oils and cause drying and chapping of the skin, while heavier liquid alkanes (those with approximately 17 or more carbon atoms per molecule) act as emollients (skin softeners). Such alkane mixtures as mineral oil and petroleum jelly can be applied as a protective film. Water and aqueous solutions such as urine will not dissolve such a film, which explains why petroleum jelly protects a baby\u2019s tender skin from diaper rash.<\/span><\/p>\n<\/div>\n<p class=\"para editable block\" id=\"gob-ch12_p04\"><span style=\"color: #000000;\">In this chapter we will investigate\u00a0the alkanes, compounds containing only two elements, carbon and hydrogen, and having only single bonds. We will also investigate alkanes that have halogens incorporated into their structure.\u00a0\u00a0Recall that halogens\u00a0are the elements in Family 7A on the periodic table and contain representative elements such as chlorine, fluorine, iodine, and bromine. There are several other kinds of hydrocarbons, distinguished by the types of bonding between carbon atoms and by the properties that result from that bonding. In Chapter\u00a08 we will examine hydrocarbons with double bonds, with triple bonds, and with a special kind of bonding called <em class=\"emphasis\">aromaticity<\/em>. Then in Chapter\u00a09, we will study some compounds considered to be derived from hydrocarbons by replacing one or more hydrogen atoms with an oxygen-containing group. Chapter 10 focuses on organic acids and bases.<\/span><\/p>\n<h5 class=\"para editable block\" style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<hr \/>\n<div class=\"section\" id=\"recognition\" lang=\"en\">\n<h3 class=\"title editable block\"><span style=\"color: #ff0000;\"><strong><span class=\"title-prefix\">7.1<\/span> Recognition of Organic Structures<\/strong><\/span><\/h3>\n<div class=\"learning_objectives editable block\" id=\"gob-ch12_s01_n01\">\n<h4 class=\"title\"><strong><span style=\"color: #000000;\">Learning Objective<\/span><\/strong><\/h4>\n<ol class=\"orderedlist\" id=\"gob-ch12_s01_l01\">\n<li><span style=\"color: #000000;\">To be able to recognize the composition and properties typical of organic and inorganic compounds.<\/span><\/li>\n<\/ol>\n<\/div>\n<p class=\"para editable block\" id=\"gob-ch12_s01_p01\"><span style=\"color: #000000;\">Scientists of the 18th and early 19th centuries studied compounds obtained from plants and animals and labeled them <em class=\"emphasis\">organic<\/em> because they were isolated from \u201corganized\u201d (living) systems. Compounds isolated from nonliving systems, such as rocks and ores, the atmosphere, and the oceans, were labeled <em class=\"emphasis\">inorganic<\/em>. For many years, scientists thought organic compounds could be made by only living organisms because they possessed a vital force found only in living systems. The vital force theory began to decline in 1828, when the German chemist Friedrich W\u00f6hler synthesized urea from inorganic starting materials. He reacted silver cyanate (AgOCN) and ammonium chloride (NH<sub class=\"subscript\"><span style=\"font-size: small;\">4<\/span><\/sub>Cl), expecting to get ammonium cyanate (NH<sub class=\"subscript\"><span style=\"font-size: small;\">4<\/span><\/sub>OCN). What he expected is described by the following equation.<\/span><\/p>\n<p><span class=\"informalequation block\" style=\"color: #000000;\"><span class=\"mathphrase\">AgOCN + NH<sub class=\"subscript\">4<\/sub>Cl \u2192 AgCl + NH<sub class=\"subscript\">4<\/sub>OCN<\/span><\/span><\/p>\n<p class=\"para editable block\" id=\"gob-ch12_s01_p02\"><span style=\"color: #000000;\">Instead, he found the product to be urea (NH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>CONH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>), a well-known organic material readily isolated from urine. This result led to a series of experiments in which a wide variety of organic compounds were made from inorganic starting materials. The vital force theory gradually went away as chemists learned that they could make many organic compounds in the laboratory.<\/span><\/p>\n<p class=\"para editable block\" id=\"gob-ch12_s01_p03\"><span style=\"color: #000000;\">Today <span class=\"margin_term\"><em><strong>organic chemistry<\/strong><\/em> has been reclassified as<\/span> the study of compounds that contain carbon, and <span class=\"margin_term\">inorganic chemistry <\/span>is the study of the chemistry of all other elements. It may seem strange that we divide chemistry into two branches\u2014one that considers compounds of only one element and one that covers the 100-plus remaining elements. However, this division seems more reasonable when we consider that of tens of millions of compounds that have been characterized, the overwhelming majority are carbon compounds.<\/span><\/p>\n<div class=\"callout editable block\" id=\"gob-ch12_s01_n02\">\n<h4 class=\"title\"><span style=\"color: #000000;\"><strong>Note<\/strong><\/span><\/h4>\n<p class=\"para\" id=\"gob-ch12_s01_p04\"><span style=\"color: #000000;\">The word <em class=\"emphasis\">organic<\/em> has different meanings. Organic fertilizer, such as cow manure, is organic in the original sense; it is derived from living organisms. Organic foods generally are foods grown without synthetic pesticides or fertilizers. Organic chemistry is the chemistry of compounds of carbon. <\/span><span style=\"color: #000000;\">Carbon is unique among the other elements in that its atoms can form stable covalent bonds with each other and with atoms of other elements in a multitude of variations. The resulting molecules can contain from one to millions of carbon atoms. <\/span><\/p>\n<\/div>\n<p class=\"para editable block\" id=\"gob-ch12_s01_p06\"><span style=\"color: #000000;\">Organic compounds, like inorganic compounds, obey all the natural laws. Often there is no clear distinction in the chemical or physical properties among organic and inorganic molecules. Nevertheless, it is useful to compare typical members of each class, as in Table\u00a07.1 (Keep in mind, however, that there are exceptions to every category in this table.) To further illustrate typical differences among organic and inorganic compounds, Table\u00a07.1 also lists properties of the inorganic compound sodium chloride (common table salt, NaCl) and the organic compound hexane (C<sub class=\"subscript\"><span style=\"font-size: small;\">6<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">14<\/span><\/sub>), a solvent that is used to extract soybean oil from soybeans (among other uses). Many compounds can be classified as organic or inorganic by the presence or absence of certain typical properties, as illustrated in Table 7.1.<\/span><\/p>\n<div class=\"table block\" id=\"gob-ch12_s01_t01\">\n<p class=\"title\"><strong><span style=\"color: #000000;\"><span class=\"title-prefix\">Table 7.1<\/span> General Contrasting Properties and Examples of Organic and Inorganic Compounds<\/span><\/strong><\/p>\n<p class=\"title\"><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/Table_7.1_i.png\"><img loading=\"lazy\" decoding=\"async\" width=\"683\" height=\"482\" class=\"alignnone wp-image-2486\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/Table_7.1_i-1024x723.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/Table_7.1_i-1024x723.png 1024w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/Table_7.1_i-300x212.png 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/Table_7.1_i-768x542.png 768w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/Table_7.1_i.png 1482w\" sizes=\"(max-width: 683px) 100vw, 683px\" \/><\/a><\/p>\n<p class=\"title\"><span style=\"color: #000000;\"><strong>Concept Review Exercises:\u00a0 <a href=\"https:\/\/docs.google.com\/a\/mail.wou.edu\/forms\/d\/1ug1zOtS6kBTQFC7tatNgac5bY9pvJn-ItXoUfQ14o90\/viewform?edit_requested=true\" target=\"_blank\">Click to Complete the Questions<\/a><\/strong><\/span><span style=\"color: #ff0000;\"><em><strong><\/strong><\/em><\/span><\/p>\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><em><strong>Key Takeaway<\/strong><\/em><\/span><\/h5>\n<\/div>\n<div class=\"key_takeaways editable block\" id=\"gob-ch12_s01_n04\">\n<ul class=\"itemizedlist\" id=\"gob-ch12_s01_l07\">\n<li><em><strong><span style=\"color: #000000;\">Organic chemistry is the study of carbon compounds, nearly all of which also contain hydrogen atoms.<\/span><\/strong><\/em><\/li>\n<\/ul>\n<\/div>\n<div class=\"qandaset block\" id=\"gob-ch12_s01_qs02\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><em><strong>More Practice<\/strong><\/em><\/span><\/h5>\n<ol class=\"qandadiv\" id=\"gob-ch12_s01_qs02_qd01\">\n<li class=\"qandaentry\" id=\"gob-ch12_s01_qs02_qd01_qa01\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s01_qs02_p01\"><span style=\"color: #000000;\">Classify each compound as organic or inorganic.<\/span><\/p>\n<ol class=\"orderedlist\" id=\"gob-ch12_s01_qs02_l01\">\n<li><span style=\"color: #000000;\">C<sub class=\"subscript\"><span style=\"font-size: small;\">6<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">10<\/span><\/sub><\/span><\/li>\n<li><span style=\"color: #000000;\">CoCl<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub><\/span><\/li>\n<li><span style=\"color: #000000;\">C<sub class=\"subscript\"><span style=\"font-size: small;\">12<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">22<\/span><\/sub>O<sub class=\"subscript\"><span style=\"font-size: small;\">11<\/span><\/sub><\/span><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s01_qs02_qd01_qa02\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s01_qs02_p02\"><span style=\"color: #000000;\">Classify each compound as organic or inorganic.<\/span><\/p>\n<ol class=\"orderedlist\" id=\"gob-ch12_s01_qs02_l03\">\n<li><span style=\"color: #000000;\">CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>NH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub><\/span><\/li>\n<li><span style=\"color: #000000;\">NaNH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub><\/span><\/li>\n<li><span style=\"color: #000000;\">Cu(NH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>)<sub class=\"subscript\"><span style=\"font-size: small;\">6<\/span><\/sub>Cl<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub><\/span><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s01_qs02_qd01_qa03\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s01_qs02_p03\"><span style=\"color: #000000;\">Which member of each pair has a higher melting point?<\/span><\/p>\n<ol class=\"orderedlist\" id=\"gob-ch12_s01_qs02_l05\">\n<li><span style=\"color: #000000;\">CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>OH and NaOH<\/span><\/li>\n<li><span style=\"color: #000000;\">CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>Cl and KCl<\/span><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s01_qs02_qd01_qa04\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s01_qs02_p04\"><span style=\"color: #000000;\">Which member of each pair has a higher melting point?<\/span><\/p>\n<ol class=\"orderedlist\" id=\"gob-ch12_s01_qs02_l07\">\n<li><span style=\"color: #000000;\">C<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">6<\/span><\/sub> and CoCl<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub><\/span><\/li>\n<li><span style=\"color: #000000;\">CH<sub class=\"subscript\"><span style=\"font-size: small;\">4<\/span><\/sub> and LiH<\/span><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div class=\"qandaset block\" id=\"gob-ch12_s01_qs02_ans\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><em><strong>Answers to odd questions:<\/strong><\/em><\/span><\/h5>\n<ol class=\"qandadiv\">\n<li class=\"qandaentry\" id=\"gob-ch12_s01_qs02_qd01_qa01_ans\">\n<div class=\"answer\">\n<ol class=\"orderedlist\" id=\"gob-ch12_s01_qs02_l02_ans\">\n<li><span style=\"color: #000000;\">organic<\/span><\/li>\n<li><span style=\"color: #000000;\">inorganic<\/span><\/li>\n<li><span style=\"color: #000000;\">organic<\/span><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s01_qs02_qd01_qa02_ans\">\n<div class=\"answer\"><\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s01_qs02_qd01_qa03_ans\">\n<div class=\"answer\">\n<ol class=\"orderedlist\" id=\"gob-ch12_s01_qs02_l06_ans\">\n<li><span style=\"color: #000000;\">NaOH<\/span><\/li>\n<li><span style=\"color: #000000;\">KCl<\/span>\n<div class=\"answer\"><\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"section\" id=\"gob-ch12_s02\" lang=\"en\">\n<hr \/>\n<h5 class=\"title editable block\" style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<hr \/>\n<h3 class=\"title editable block\" id=\"introalkanes\"><strong><span style=\"color: #ff0000;\"><span class=\"title-prefix\">7.2<\/span> Introduction to Alkanes<\/span><\/strong><\/h3>\n<p><span style=\"color: #000000;\">Alkanes are organic compounds that consist entirely of single-bonded carbon and hydrogen atoms and lack any other functional groups.\u00a0Alkanes have the general formula <span class=\"MathJax\" id=\"MathJax-Element-1-Frame\" role=\"presentation\"><span class=\"math\" id=\"MathJax-Span-1\"><span class=\"mrow\" id=\"MathJax-Span-2\"><span class=\"msubsup\" id=\"MathJax-Span-3\"><span class=\"mi\" id=\"MathJax-Span-4\">C<\/span><sub><span class=\"mi\" id=\"MathJax-Span-5\">n<\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-6\"><span class=\"mi\" id=\"MathJax-Span-7\">H<\/span><span class=\"texatom\" id=\"MathJax-Span-8\"><span class=\"mrow\" id=\"MathJax-Span-9\"><sub><span class=\"mn\" id=\"MathJax-Span-10\">2<\/span><span class=\"mi\" id=\"MathJax-Span-11\">n<\/span><\/sub><span class=\"mo\" id=\"MathJax-Span-12\">+<\/span><span class=\"mn\" id=\"MathJax-Span-13\">2<\/span><\/span><\/span><\/span><\/span><\/span><\/span> and can be subdivided into the following\u00a0three groups: the linear straight-chain alkanes, branched alkanes, and\u00a0cycloalkanes (Fig. 7.2). Alkanes are also <em class=\"italic\">saturated hydrocarbons, <\/em>that is all of the carbon atoms are &#8216;saturated&#8217; with hydrogen atoms and do not contain any carbon-carbon double bonds or triple bonds.\u00a0Alkanes are the simplest and least reactive\u00a0hydrocarbon\u00a0species containing only carbons and hydrogens. They are commercially very important, being the principal constituent of gasoline and lubricating oils and are extensively employed in organic chemistry; though the role of pure alkanes (such as hexanes) is delegated mostly to solvents. The distinguishing feature of an alkane, making it distinct from other compounds that also exclusively contain carbon and hydrogen, is its lack of\u00a0unsaturation. That is to say, it contains no double or triple bonds, which are highly reactive in organic chemistry. Though not totally devoid of reactivity, their lack of reactivity under most laboratory conditions makes them a relatively uninteresting, though very important component of organic chemistry. As you will learn about later, the energy confined within the carbon-carbon bond and the carbon-hydrogen bond is quite high and their rapid oxidation produces a large amount of heat, typically in the form of fire.<\/span><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/types-of-alkanes-ii.png\"><img loading=\"lazy\" decoding=\"async\" width=\"609\" height=\"416\" class=\"alignnone wp-image-2497\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/types-of-alkanes-ii.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/types-of-alkanes-ii.png 865w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/types-of-alkanes-ii-300x205.png 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/types-of-alkanes-ii-768x524.png 768w\" sizes=\"(max-width: 609px) 100vw, 609px\" \/><\/a><\/p>\n<p><span style=\"color: #000000;\"><strong>Figure 7.2. Examples of Alkanes<\/strong><\/span><\/p>\n<hr \/>\n<div class=\"figure large editable block\" id=\"gob-ch12_s02_f01\">\n<h4 class=\"title\" id=\"straight\"><strong><span style=\"color: #000000;\">Straight Chain Alkanes<\/span><\/strong><\/h4>\n<p class=\"title\"><span style=\"color: #000000;\">The straight chain alkanes, methane (CH<sub class=\"subscript\"><span style=\"font-size: small;\">4<\/span><\/sub>), ethane (C<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">6<\/span><\/sub>), and propane (C<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">8<\/span><\/sub>)\u00a0represent the beginning of a series of compounds in which any two members in a sequence differ by one carbon atom and two hydrogen atoms\u2014namely, a CH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub> unit (Fig. 7.3)\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" width=\"703\" height=\"196\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/ceb9608ec0b972189e25b54fb971bb57.jpg\" \/><\/p>\n<\/div>\n<p class=\"para editable block\"><strong><span style=\"color: #000000;\"><span class=\"title-prefix\">Figure\u00a07.3<\/span> The Three Simplest Alkanes<\/span><\/strong><\/p>\n<div class=\"figure large editable block\" id=\"gob-ch12_s02_f02\">\n<p class=\"title\"><span style=\"color: #000000;\">The first 10 members of this series are given in Table 7.2.\u00a0 Note that as you increase the length of the carbon chain, the number of possible different structural isomers also increases.<\/span><\/p>\n<p>&nbsp;<\/p>\n<\/div>\n<div class=\"table block\" id=\"gob-ch12_s02_t01\">\n<p class=\"title\"><strong><span style=\"color: #000000;\"><span class=\"title-prefix\">Table 7.2<\/span> The First 10 Straight-Chain Alkanes<\/span><\/strong><\/p>\n<p class=\"title\"><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/table_7.2.png\"><img loading=\"lazy\" decoding=\"async\" width=\"684\" height=\"369\" class=\"alignnone wp-image-2566\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/table_7.2-1024x553.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/table_7.2-1024x553.png 1024w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/table_7.2-300x162.png 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/table_7.2-768x415.png 768w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/table_7.2.png 1573w\" sizes=\"(max-width: 684px) 100vw, 684px\" \/><\/a><\/p>\n<\/div>\n<p class=\"para editable block\" id=\"gob-ch12_s02_p06\"><span style=\"color: #000000;\">From propane (C<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">8) <\/span><\/sub><span style=\"font-size: small;\">o<\/span>nward, you will notice that the only difference between longer chain hydrocarbons involves the addition of\u00a0\u00a0 CH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub> units\u00a0as you move\u00a0up the series (Fig. 7.4). Any family of compounds in which adjacent members differ from each other by a definite factor (here a CH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub> group) is called a <span class=\"margin_term\"><em><strong><a class=\"glossterm\" style=\"color: #000000;\">homologous series<\/a><\/strong><\/em><span class=\"glossdef\">, and can be defined mathematically. <\/span><\/span>The members of such a series, called <strong><em class=\"emphasis\">homologs. <\/em><\/strong>In organic chemistry, homologs have properties that vary in a regular and predictable manner. Thus, the principle of homology gives organization to organic chemistry in much the same way that the periodic table gives organization to inorganic chemistry. Instead of a bewildering array of individual carbon compounds, we can study a few members of a homologous series and from them deduce some of the properties of other compounds in the series.<\/span><\/p>\n<div class=\"figure large editable block\" id=\"gob-ch12_s02_f03\">\n<p class=\"title\"><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" width=\"695\" height=\"319\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/1e8b019bfe6949342d49dc98e9c1335f.jpg\" \/><\/p>\n<p class=\"para\"><strong><span style=\"color: #000000;\"><span class=\"title-prefix\">Figure\u00a07.4<\/span> Members of a Homologous Series<\/span><\/strong><\/p>\n<p class=\"para\"><span style=\"color: #000000;\">In Figure 7.4, note that each succeeding formula incorporates one carbon atom and two hydrogen atoms more than the previous formula. The principle of homology allows us to write a general formula for alkanes: C<sub class=\"subscript\"><em class=\"emphasis\"><span style=\"font-size: small;\">n<\/span><\/em><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub><sub class=\"subscript\"><em class=\"emphasis\"><span style=\"font-size: small;\">n<\/span><\/em><\/sub><sub class=\"subscript\"><span style=\"font-size: small;\">+ 2<\/span><\/sub>. Using this formula, we can write a molecular formula for any alkane with a given number of carbon atoms. For example, an alkane with eight carbon atoms has the molecular formula C<sub class=\"subscript\"><span style=\"font-size: small;\">8<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">(2 \u00d7 8) + 2<\/span><\/sub> = C<sub class=\"subscript\"><span style=\"font-size: small;\">8<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">18<\/span><\/sub>.<\/span><\/p>\n<div class=\"qandaset block\" id=\"gob-ch12_s02_qs01\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><strong><em>Concept Review Exercises<\/em><\/strong><\/span><\/h5>\n<ol class=\"qandadiv\" id=\"gob-ch12_s02_qs01_qd01\">\n<li class=\"qandaentry\" id=\"gob-ch12_s02_qs01_qd01_qa01\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s02_qs01_p01\"><span style=\"color: #000000;\">In the homologous series of alkanes, what is the molecular formula for the member just above C<sub class=\"subscript\"><span style=\"font-size: small;\">8<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">18<\/span><\/sub>?<\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s02_qs01_qd01_qa02\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s02_qs01_p03\"><span style=\"color: #000000;\">Use the general formula for alkanes to write the molecular formula of the alkane with 12 carbon atoms.<\/span><\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div class=\"qandaset block\" id=\"gob-ch12_s02_qs01_ans\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><em><strong>Answers<\/strong><\/em><\/span><\/h5>\n<ol class=\"qandadiv\">\n<li class=\"qandaentry\" id=\"gob-ch12_s02_qs01_qd01_qa01_ans\">\n<div class=\"answer\">\n<p class=\"para\" id=\"gob-ch12_s02_qs01_p02_ans\"><span style=\"color: #000000;\">C<sub class=\"subscript\"><span style=\"font-size: small;\">9<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">20<\/span><\/sub><\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s02_qs01_qd01_qa02_ans\">\n<div class=\"answer\">\n<p class=\"para\" id=\"gob-ch12_s02_qs01_p04_ans\"><span style=\"color: #000000;\">C<sub class=\"subscript\"><span style=\"font-size: small;\">12<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">26<\/span><\/sub><\/span><\/p>\n<h5 class=\"para\" style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<hr \/>\n<h4 class=\"para\" id=\"branched\"><strong><span style=\"color: #000000;\">Branched Chain Alkanes<\/span><\/strong><\/h4>\n<p class=\"title editable block\"><span style=\"color: #000000;\">We can write the structure of butane (C<sub class=\"subscript\"><span style=\"font-size: small;\">4<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">10<\/span><\/sub>) by stringing four carbon atoms in a row,<\/span><\/p>\n<p><span class=\"informalequation block\" style=\"color: #000000;\"><span class=\"mathphrase\">\u2013C\u2013C\u2013C\u2013C\u2013<\/span><\/span><\/p>\n<p class=\"para editable block\" id=\"gob-ch12_s03_p02\"><span style=\"color: #000000;\">and then adding enough hydrogen atoms to give each carbon atom four bonds:<\/span><\/p>\n<div class=\"informalfigure large block\"><img loading=\"lazy\" decoding=\"async\" width=\"670\" height=\"137\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/29fd4abea1950382c70d69cd8a344553.jpg\" \/><\/div>\n<p class=\"para editable block\" id=\"gob-ch12_s03_p03\"><span style=\"color: #000000;\">The compound butane has this structure, but there is another way to put 4 carbon atoms and 10 hydrogen atoms together. Place 3 of the carbon atoms in a row and then branch the fourth one off the middle carbon atom:<\/span><\/p>\n<div class=\"informalfigure large block\"><img loading=\"lazy\" decoding=\"async\" width=\"673\" height=\"91\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/3dcf40975b53e8e43d15845baa63ec74.jpg\" \/><\/div>\n<p class=\"para editable block\" id=\"gob-ch12_s03_p04\"><span style=\"color: #000000;\">Now we add enough hydrogen atoms to give each carbon four bonds.<\/span><\/p>\n<div class=\"informalfigure large block\"><img loading=\"lazy\" decoding=\"async\" width=\"672\" height=\"246\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/c3556577ef9e4710216fab14285f486b.jpg\" \/><\/div>\n<p class=\"para editable block\" id=\"gob-ch12_s03_p05\"><span style=\"color: #000000;\">There is a hydrocarbon that corresponds to this structure, which means that two different compounds have the same molecular formula (C<sub class=\"subscript\"><span style=\"font-size: small;\">4<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">10<\/span><\/sub><span style=\"font-size: small;\">), but a different arrangement of the atoms in space<\/span>.\u00a0 Recall that compounds having the same molecular formula but a different arrangement in\u00a0space\u00a0are called <strong><em>structural\u00a0<span class=\"margin_term\"><a class=\"glossterm\" style=\"color: #000000;\">isomers<\/a><\/span><\/em><\/strong>.\u00a0Structural isomers\u00a0have different chemical and physical properties. Figure 7.5 shows the ball and stick model for the straight chain butane and the branched isomer, isobutane.<\/span><\/p>\n<div class=\"figure large editable block\" id=\"gob-ch12_s03_f01\">\n<p><img loading=\"lazy\" decoding=\"async\" width=\"691\" height=\"324\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/92ca38faa079c802242a1bf649e6bc1e.jpg\" \/><\/p>\n<p class=\"para\"><span style=\"color: #000000;\"><strong><span class=\"title-prefix\">Figure\u00a07.5<\/span> Butane and Isobutane.<\/strong> The ball-and-stick models of these two compounds show them to be isomers; both have the molecular formula C<sub class=\"subscript\"><span style=\"font-size: small;\">4<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">10<\/span><\/sub>.<\/span><\/p>\n<\/div>\n<p class=\"para editable block\" id=\"gob-ch12_s03_p06\"><span style=\"color: #000000;\">Notice that C<sub class=\"subscript\"><span style=\"font-size: small;\">4<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">10<\/span><\/sub> is depicted with a bent chain in Figure\u00a07.5. The four-carbon chain may be bent in various ways because the groups can rotate freely about the C\u2013C bonds. However, this rotation does not change the identity of the compound. It is important to realize that bending a chain does <em class=\"emphasis\">not<\/em> change the identity of the compound; all of the following represent the same compound:<\/span><\/p>\n<div class=\"informalfigure large block\"><img loading=\"lazy\" decoding=\"async\" width=\"681\" height=\"190\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/141fbabea40922728ad040f7576ab911.jpg\" \/><\/div>\n<p class=\"para editable block\" id=\"gob-ch12_s03_p07\"><span style=\"color: #000000;\">The formula of isobutane shows a continuous chain of three carbon atoms only, with the fourth attached as a branch off the middle carbon atom of the continuous chain.<\/span><\/p>\n<p class=\"para editable block\" id=\"gob-ch12_s03_p08\"><span style=\"color: #000000;\">Unlike C<sub class=\"subscript\"><span style=\"font-size: small;\">4<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">10<\/span><\/sub>, the compounds methane (CH<sub class=\"subscript\"><span style=\"font-size: small;\">4<\/span><\/sub>), ethane (C<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">6<\/span><\/sub>), and propane (C<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">8<\/span><\/sub>) do not exist in isomeric forms because there is only one way to arrange the atoms in each formula so that each carbon atom has four bonds.<\/span><\/p>\n<p class=\"informalfigure large block\"><em><span style=\"color: #ff0000;\"><strong>Note<\/strong><\/span><\/em><\/p>\n<div class=\"callout editable block\" id=\"gob-ch12_s03_n02\">\n<p class=\"para\" id=\"gob-ch12_s03_p10\"><span style=\"color: #000000;\">A continuous (unbranched) chain of carbon atoms is often called a <em class=\"emphasis\">straight chain<\/em> even though the tetrahedral arrangement about each carbon gives it a zigzag shape. Straight-chain alkanes are sometimes called <em class=\"emphasis\">normal alkanes<\/em>, and their names are given the prefix <em class=\"emphasis\">n<\/em>-. For example, butane is called <em class=\"emphasis\">n<\/em>-butane.<\/span><\/p>\n<div class=\"qandaset block\" id=\"gob-ch12_s03_qs01\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><em><strong>Concept Review Exercises<\/strong><\/em><\/span><\/h5>\n<ol class=\"qandadiv\" id=\"gob-ch12_s03_qs01_qd01\">\n<li class=\"qandaentry\" id=\"gob-ch12_s03_qs01_qd01_qa01\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s03_qs01_p01\"><span style=\"color: #000000;\">In alkanes, can there be a two-carbon branch off the second carbon atom of a four-carbon chain? Explain.<\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s03_qs01_qd01_qa02\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s03_qs01_p03\"><span style=\"color: #000000;\">A student is asked to write structural formulas for two different hydrocarbons having the molecular formula C<sub class=\"subscript\"><span style=\"font-size: small;\">5<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">12<\/span><\/sub>. She writes one formula with all five carbon atoms in a horizontal line and the other with four carbon atoms in a line, with a CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub> group extending down from the first attached to the third carbon atom. Do these structural formulas represent different molecular formulas? Explain why or why not.<\/span><\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div class=\"qandaset block\" id=\"gob-ch12_s03_qs01_ans\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><strong><em>Answers<\/em><\/strong><\/span><\/h5>\n<ol class=\"qandadiv\">\n<li class=\"qandaentry\" id=\"gob-ch12_s03_qs01_qd01_qa01_ans\">\n<div class=\"answer\">\n<p class=\"para\" id=\"gob-ch12_s03_qs01_p02_ans\"><span style=\"color: #000000;\">No; the branch would make the longest continuous chain of five carbon atoms.<\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s03_qs01_qd01_qa02_ans\">\n<div class=\"answer\">\n<p class=\"para\" id=\"gob-ch12_s03_qs01_p04_ans\"><span style=\"color: #000000;\">No; both are five-carbon continuous chains.<\/span><\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div class=\"key_takeaways editable block\" id=\"gob-ch12_s03_n04\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><strong><em>Key Takeaway<\/em><\/strong><\/span><\/h5>\n<ul class=\"itemizedlist\" id=\"gob-ch12_s03_l03\">\n<li><span style=\"color: #000000;\">Alkanes with four or more carbon atoms can exist in isomeric forms.<\/span><\/li>\n<\/ul>\n<\/div>\n<div class=\"qandaset block\" id=\"gob-ch12_s03_qs02\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><em>Exercises<\/em><\/span><\/h5>\n<ol class=\"qandadiv\" id=\"gob-ch12_s03_qs02_qd01\">\n<li class=\"qandaentry\" id=\"gob-ch12_s03_qs02_qd01_qa01\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s03_qs02_p01\"><span style=\"color: #000000;\">Briefly identify the important distinctions between a straight-chain alkane and a branched-chain alkane.<\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s03_qs02_qd01_qa03\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s03_qs02_p05\"><span style=\"color: #000000;\">Draw the structural isomers for the following alkanes.<\/span><\/p>\n<ol class=\"orderedlist\" id=\"gob-ch12_s03_qs02_l01\">\n<li>\n<div class=\"informalfigure large\"><img loading=\"lazy\" decoding=\"async\" width=\"413\" height=\"83\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/f4e000cacc0fd570612e6713f728db25.jpg\" \/><\/div>\n<\/li>\n<li>\n<div class=\"informalfigure large\"><img loading=\"lazy\" decoding=\"async\" width=\"408\" height=\"82\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/e2be06c2f6562f3104ee3c4ab6d2650c.jpg\" \/><\/div>\n<ol class=\"orderedlist\" id=\"gob-ch12_s03_qs02_l03\"><\/ol>\n<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s03_qs02_qd01_qa05\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s03_qs02_p07\"><span style=\"color: #000000;\">Indicate whether the structures in each set represent the same compound or isomers.<\/span><\/p>\n<ol class=\"orderedlist\" id=\"gob-ch12_s03_qs02_l05\">\n<li>\n<p class=\"para\"><span style=\"color: #000000;\">CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>CH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>CH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub> and<\/span><\/p>\n<div class=\"informalfigure large\"><img loading=\"lazy\" decoding=\"async\" width=\"407\" height=\"56\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/cfa5bb309c438a57ce83ced2080e9320.jpg\" \/><\/div>\n<\/li>\n<li>\n<p class=\"para\"><span style=\"color: #000000;\">CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>CH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>CH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>CH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub> and<\/span><\/p>\n<div class=\"informalfigure large\"><img loading=\"lazy\" decoding=\"async\" width=\"418\" height=\"53\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/80d3cfc03399873095a6f648297668d7.jpg\" \/><\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div class=\"qandaset block\" id=\"gob-ch12_s03_qs02_ans\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><strong><em>Answers<\/em><\/strong><\/span><\/h5>\n<ol class=\"qandadiv\">\n<li class=\"qandaentry\" id=\"gob-ch12_s03_qs02_qd01_qa01_ans\">\n<div class=\"answer\">\n<p class=\"para\" id=\"gob-ch12_s03_qs02_p02_ans\"><span style=\"color: #000000;\">Straight-chain alkanes and branched-chain alkanes have different properties as well as different structures.<\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s03_qs02_qd01_qa02_ans\">\n<div class=\"answer\"><\/div>\n<div class=\"answer\"><\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s03_qs02_qd01_qa05_ans\">\n<div class=\"answer\">\n<ol class=\"orderedlist\" id=\"gob-ch12_s03_qs02_l06_ans\">\n<li><span style=\"color: #000000;\">no<\/span><\/li>\n<li><span style=\"color: #000000;\">yes<\/span><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div class=\"section\" id=\"gob-ch12_s04\" lang=\"en\">\n<h2 class=\"title editable block\"><\/h2>\n<div class=\"key_takeaways editable block\" id=\"gob-ch12_s04_n03\">\n<ul class=\"itemizedlist\" id=\"gob-ch12_s04_l02\"><\/ul>\n<\/div>\n<div class=\"qandaset block\" id=\"gob-ch12_s04_qs01\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><strong><em>Additional Practice<\/em><\/strong><\/span><\/h5>\n<ol class=\"qandadiv\" id=\"gob-ch12_s04_qs01_qd01\">\n<li class=\"qandaentry\" id=\"gob-ch12_s04_qs01_qd01_qa01\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s04_qs01_p01\"><span style=\"color: #000000;\">Write the condensed structural formula for each structural formula.<\/span><\/p>\n<ol class=\"orderedlist\" id=\"gob-ch12_s04_qs01_l01\">\n<li>\n<div class=\"informalfigure large\"><img loading=\"lazy\" decoding=\"async\" width=\"428\" height=\"83\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/ee2732e9b3260c19a4b574634b9a6ebb.jpg\" \/><\/div>\n<\/li>\n<li>\n<div class=\"informalfigure large\"><img loading=\"lazy\" decoding=\"async\" width=\"427\" height=\"85\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/9015dee78ce51648b28fe5e89e114fa2.jpg\" \/><\/div>\n<\/li>\n<li>\n<div class=\"informalfigure large\"><img loading=\"lazy\" decoding=\"async\" width=\"430\" height=\"88\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/49ce63b9e97b73e67c87a4ed581b412d.jpg\" \/><\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s04_qs01_qd01_qa02\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s04_qs01_p02\"><span style=\"color: #000000;\">A condensed structural formula for isohexane can be written as (CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>)<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>CHCH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>CH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>. Draw the line-angle formula for isohexane.<\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s04_qs01_qd01_qa03\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s04_qs01_p03\"><span style=\"color: #000000;\">Draw a line-angle formula for the compound CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>CH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>CH(CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>)CH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>CH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>.<\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s04_qs01_qd01_qa04\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s04_qs01_p04\"><span style=\"color: #000000;\">Give the structural formula for the compound represented by this line-angle formula:<\/span><\/p>\n<div class=\"informalfigure large\"><img loading=\"lazy\" decoding=\"async\" width=\"431\" height=\"56\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/752d6a46a05f28c6e614e120e8cf1a08.jpg\" \/><\/div>\n<\/div>\n<h5 class=\"informalfigure large\" style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<\/li>\n<\/ol>\n<\/div>\n<div class=\"qandaset block\">\n<hr \/>\n<\/div>\n<div class=\"qandaset block\" id=\"cycloalkanes\"><span style=\"color: #000000;\"><strong>Cycloalkanes<\/strong><\/span><\/div>\n<\/div>\n<\/div>\n<\/div>\n<p><span style=\"color: #000000;\"><span><\/span>Cycloalkanes are very important in components of food, pharmaceutical drugs, and much more. However, to\u00a0use cycloalkanes in\u00a0such\u00a0applications,\u00a0we must\u00a0know the effects, functions, properties, and structures of cycloalkanes. Cycloalkanes are alkanes that are in the form of a ring; hence, the prefix<strong><em> cyclo-<\/em> <\/strong>is used to name these alkanes.<strong><em>\u00a0<\/em><\/strong>Stable cycloalkanes cannot be formed with carbon chains of just any length. Recall that in alkanes, carbon adopts the\u00a0tetrahedral geometry in which the angles between bonds are 109.5\u00b0. <\/span><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/Ch4-structure.png\"><img loading=\"lazy\" decoding=\"async\" width=\"172\" height=\"178\" class=\"alignnone size-full wp-image-2563\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/Ch4-structure.png\" \/><\/a><span style=\"color: #000000;\">Source:<\/span><a href=\"https:\/\/commons.wikimedia.org\/w\/index.php?curid=540020\"> Wikipedia<\/a><\/p>\n<p><span style=\"color: #000000;\">For some cycloalkanes to form, the angle between bonds must deviate from this ideal angle, an effect known as\u00a0<em><b>angle strain<\/b><\/em>. Additionally, some hydrogen atoms may come into closer proximity with each other than is desirable (become eclipsed), an effect called\u00a0<em><b>torsional strain<\/b><\/em>. These destabilizing effects, angle strain and torsional strain are known together as\u00a0<em><b>ring strain<\/b><\/em>. The smaller cycloalkanes, cyclopropane and cyclobutane, have particularly high ring strains because their bond angles deviate substantially from 109.5\u00b0 and their hydrogens eclipse each other.\u00a0Thus, both of these ring conformations are highly unfavorable and unstable.\u00a0Cyclopentane is a more stable molecule with a small amount of ring strain, while\u00a0cyclohexane\u00a0is able to adopt the perfect geometry of a cycloalkane in which all angles are the ideal 109.5\u00b0 and no hydrogens are eclipsed; it has no ring strain at all. Cycloalkanes larger than cyclohexane have ring strain and are not as commonly encountered in organic chemistry. Figure 7.6 provides examples of cycloalkane structures.<\/span><\/p>\n<div class=\"mt-section\" id=\"section_1\">\n<p><span id=\"Ring_Strain_and_the_Structures_of_Cycloalkanes\"><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/ycloalkanes.png\"><img loading=\"lazy\" decoding=\"async\" width=\"684\" height=\"691\" class=\"alignnone wp-image-2562\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/ycloalkanes-1012x1024.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/ycloalkanes-1012x1024.png 1012w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/ycloalkanes-296x300.png 296w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/ycloalkanes-768x777.png 768w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/ycloalkanes.png 1057w\" sizes=\"(max-width: 684px) 100vw, 684px\" \/><\/a><\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>Figure 7.6. Representative Cycloalkane Structures.<\/strong> Average bond angles and strain energy are indicated. <\/span><\/p>\n<p class=\"editable\"><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<hr \/>\n<\/div>\n<div class=\"callout editable block\" id=\"gob-ch12_s09_n02\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><em><strong>To Your Health: Cyclopropane as an Anesthetic<\/strong><\/em><\/span><\/h5>\n<p class=\"para\" id=\"gob-ch12_s09_p02\"><span style=\"color: #000000;\">With its boiling point of \u221233\u00b0C, cyclopropane is a gas at room temperature. It is also a potent, quick-acting anesthetic with few undesirable side effects in the body. It is no longer used in surgery, however, because it forms explosive mixtures with air at nearly all concentrations.<\/span><\/p>\n<h5 class=\"para\" style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<\/div>\n<hr \/>\n<h4 id=\"classification\"><strong><span style=\"color: #000000;\">Classification of Carbon Bonds<\/span><\/strong><\/h4>\n<p><span style=\"color: #000000;\">Carbon atoms participating in chemical bonds within a molecule can be classified based on the number of carbon-carbon bonds that are formed.\u00a0<\/span><\/p>\n<ul>\n<li><span style=\"color: #000000;\"><b>primary carbon atom<\/b>: one carbon neighbor<\/span><\/li>\n<li><span style=\"color: #000000;\"><b>secondary carbon atom<\/b>: two carbon neighbors<\/span><\/li>\n<li><span style=\"color: #000000;\"><b>tertiary carbon atom<\/b>: three carbon neighbors<\/span><\/li>\n<li><span style=\"color: #000000;\"><b>quaternary carbon atom<\/b>: four carbon neighbors<\/span><\/li>\n<\/ul>\n<\/div>\n<p><span style=\"color: #000000;\">The number of carbon neighbors\u00a0that a\u00a0carbon atom has\u00a0can help determine the reactivity of that carbon position.\u00a0 Thus, it is important to be able to recognize whether a carbon atom is primary, secondary, tertiary, or quaternary in its structure (Fig. 7.7).<\/span><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/primary-carbon.png\"><img loading=\"lazy\" decoding=\"async\" width=\"686\" height=\"173\" class=\"alignnone wp-image-2504\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/primary-carbon.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/primary-carbon.png 993w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/primary-carbon-300x76.png 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/primary-carbon-768x193.png 768w\" sizes=\"(max-width: 686px) 100vw, 686px\" \/><\/a><\/p>\n<p><span style=\"color: #000000;\"><strong>Figure 7.7. Classification of carbon atoms as primary, secondary, tertiary, or quaternary.<\/strong>\u00a0 In the molecules above, the center carbon is evaluated for the number of carbon atoms that are bonded directly with the center carbon.\u00a0 A primary carbon is bonded to one carbon, a secondary carbon is bonded to two carbons, a tertiary carbon is bonded to three carbons, and a quaternary carbon is bonded to four carbons.<\/span><\/p>\n<hr \/>\n<div class=\"section\" id=\"gob-ch12_s02\" lang=\"en\">\n<p><span style=\"color: #000000;\">Within any given molecule, each carbon atom can be classified (Fig. 7.8).<\/span><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/carbon-atoms.png\"><img loading=\"lazy\" decoding=\"async\" width=\"281\" height=\"205\" class=\"alignnone size-full wp-image-2506\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/carbon-atoms.png\" \/><\/a><\/p>\n<p><span style=\"color: #000000;\"><strong>Figure 7.8.\u00a0 Classification of Carbon Atoms Within a Molecule<\/strong><\/span><\/p>\n<h5 style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<hr \/>\n<h3 id=\"properties\"><span style=\"color: #ff0000;\"><strong><span class=\"title-prefix\">7.3 <\/span>Properties of\u00a0Alkanes<\/strong><\/span><\/h3>\n<p><span style=\"color: #000000;\">Alkanes are the simplest family of hydrocarbons &#8211; compounds containing carbon and hydrogen only with only carbon-hydrogen bonds and carbon-carbon single bonds. Alkanes are not very reactive and have little biological activity; all alkanes are colorless and odorless. Because alkanes have relatively predictable physical properties and undergo relatively few chemical reactions other than combustion, they serve as a basis of comparison for the properties of many other organic compound families. Let\u2019s consider their physical properties first.<\/span><\/p>\n<p class=\"para editable block\" id=\"gob-ch12_s06_p02\"><span style=\"color: #000000;\">Table\u00a07.3 describes some of the properties of some of the first 10 straight-chain alkanes.\u00a0 Nearly all alkanes have densities less than 1.0 g\/mL and are therefore less dense than water (the density of H<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>O is 1.00 g\/mL at 20\u00b0C). <\/span><\/p>\n<div class=\"table block\" id=\"gob-ch12_s06_t01\">\n<p class=\"title\"><strong><span style=\"color: #000000;\"><span class=\"title-prefix\">Table\u00a07.3<\/span> Physical Properties of Some Alkanes<\/span><\/strong><\/p>\n<p class=\"title\"><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/table_7.3.png\"><img loading=\"lazy\" decoding=\"async\" width=\"686\" height=\"249\" class=\"alignnone wp-image-2568\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/table_7.3-1024x372.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/table_7.3-1024x372.png 1024w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/table_7.3-300x109.png 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/table_7.3-768x279.png 768w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/table_7.3.png 1957w\" sizes=\"(max-width: 686px) 100vw, 686px\" \/><\/a><\/p>\n<\/div>\n<div class=\"figure small editable block\" id=\"gob-ch12_s06_f01\">\n<hr \/>\n<div class=\"copyright\">\n<div class=\"callout editable block\" id=\"gob-ch12_s06_n02\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><em><strong>Looking Closer: Gas Densities and Fire Hazards<\/strong><\/em><\/span><\/h5>\n<p class=\"para\" id=\"gob-ch12_s06_p03\"><span style=\"color: #000000;\">Table 7.3 indicates that the first four members of the alkane series are gases at ordinary temperatures. Natural gas is composed chiefly of methane, which has a density of about 0.67 g\/L. The density of air is about 1.29 g\/L. Because natural gas is less dense than air, it rises. When a natural-gas leak is detected and shut off in a room, the gas can be removed by opening an upper window. On the other hand, bottled gas can be either propane (density 1.88 g\/L) or butanes (a mixture of butane and isobutane; density about 2.5 g\/L). Both are much heavier than air (density 1.2 g\/L). If bottled gas escapes into a building, it collects near the floor. This presents a much more serious fire hazard than a natural-gas leak because it is more difficult to rid the room of the heavier gas.<\/span><\/p>\n<h5 class=\"para\" style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<hr \/>\n<\/div>\n<\/div>\n<\/div>\n<h4 class=\"editable\" id=\"meltingboiling\"><strong><span style=\"color: #000000;\">Melting Points and Boiling Points<\/span><\/strong><\/h4>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">Both the melting points and boiling points of alkanes are characteristic of the intermolecular forces found between the molecules. The electronegativity difference between carbon and hydrogen (2.1 &#8211; 1.9 = 0.2) is small; therefore,\u00a0the C-H bond is nonpolar, meaning that the only attractions between one molecule and its neighbors will be\u00a0London\u00a0dispersion forces. These\u00a0 forces will be very small for a molecule like methane but will increase as the size of the molecules increase. Therefore, the melting and\u00a0boiling points of the alkanes increases with the molecular size, due to the increase in London dispersion forces. (i.e. the intermolecular forces are stronger in larger hydrocarbons, therefore, more energy is required to cause phase changes).\u00a0Figure 7.9 shows the melting\u00a0and boiling point trends for the first 16 hydrocarbons.\u00a0Notice that the first four alkanes are gases at room temperature, and solids do not start to appear until about C<sub>17<\/sub>H<sub>36<\/sub>.<\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" width=\"561\" height=\"278\" class=\"alignnone wp-image-2589\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/alkane-melting-an-boiling-points-1024x507.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/alkane-melting-an-boiling-points-1024x507.png 1024w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/alkane-melting-an-boiling-points-300x148.png 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/alkane-melting-an-boiling-points-768x380.png 768w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/alkane-melting-an-boiling-points.png 1029w\" sizes=\"(max-width: 561px) 100vw, 561px\" \/><span style=\"color: #000000;\"><strong><span style=\"font-family: Helvetica,Arial;\"><\/span><\/strong><\/span><\/p>\n<p><span style=\"color: #000000;\"><strong><span style=\"font-family: Helvetica,Arial;\">Figure 7.9. Melting Points and Boiling Points for Straight Chain Alkanes<\/span><\/strong><\/span><\/p>\n<p align=\"center\" style=\"text-align: left;\"><span style=\"color: #000000;\">Adapted from:<\/span> <a href=\"https:\/\/commons.wikimedia.org\/w\/index.php?curid=18580045\">Techstepp<\/a><\/p>\n<hr \/>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">Regarding isomers, the more branched the chain, the lower the boiling point tends to be.\u00a0London dispersion forces are smaller for shorter molecules and only operate over very short distances between one molecule and its neighbors. It is more difficult for short, bulky molecules (with substantial amounts of branching) to lie close together (compact)\u00a0compared with\u00a0long, thin molecules. Cycloalkanes are similar to alkanes in their general physical properties, but they have higher <span>boiling points<\/span>, <span>melting points<\/span>, and <span>densities<\/span> than alkanes. This is due to stronger <span>London forces<\/span> because the ring shape allows for a larger area of contact.<\/span><\/span><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/BP-alkanes.png\"><img loading=\"lazy\" decoding=\"async\" width=\"682\" height=\"840\" class=\"alignnone wp-image-2494\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/BP-alkanes-831x1024.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/BP-alkanes-831x1024.png 831w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/BP-alkanes-243x300.png 243w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/BP-alkanes-768x947.png 768w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/BP-alkanes.png 1057w\" sizes=\"(max-width: 682px) 100vw, 682px\" \/><\/a><\/p>\n<hr \/>\n<h5 class=\"editable\" style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<h4 class=\"editable\" id=\"solubility\"><span style=\"color: #000000;\"><strong>Solubility<\/strong><\/span><\/h4>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">Alkanes (both normal and cycloalkanes) are virtually insoluble in water but dissolve in organic solvents. The liquid alkanes are good solvents for many other covalent compounds. When a molecular substance dissolves in water, the following must occur:<\/span><\/span><\/p>\n<ul>\n<li><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">breaking of\u00a0the intermolecular forces within the substance. In the case of the alkanes, these are the London dispersion forces.<\/span><\/span><\/li>\n<li><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">breaking of\u00a0the intermolecular forces in the water so that the substance can fit between the water molecules. In water, the\u00a0primary intermolecular attractions are hydrogen bonds.<\/span><\/span><\/li>\n<\/ul>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Helvetica,Arial;\">Breaking either of these attractions requires energy, although the amount of energy required\u00a0to break the\u00a0London dispersion forces in a compound, such as methane, is\u00a0relatively negligible; this is not true of the hydrogen bonds in water. Recall that hydrogen bonds are much stronger.\u00a0 <\/span><\/span><\/p>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">To simplify, a substance will dissolve if sufficient energy is released when the new bonds are\u00a0formed between the substance and the water to make up for the energy required to break the original attractions. The only new attractions between the alkane and the water molecules are the\u00a0London dispersion\u00a0forces. These\u00a0forces to do not\u00a0release a sufficient amount of energy to compensate for the energy required to break the hydrogen bonds in water. Therefore, the\u00a0alkane does not dissolve as shown in Figure 7.10.<\/span><\/span><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/oil-and-wate.png\"><img loading=\"lazy\" decoding=\"async\" width=\"413\" height=\"565\" class=\"wp-image-2500 alignleft\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/oil-and-wate-748x1024.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/oil-and-wate-748x1024.png 748w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/oil-and-wate-219x300.png 219w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/oil-and-wate-768x1052.png 768w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/oil-and-wate.png 777w\" sizes=\"(max-width: 413px) 100vw, 413px\" \/><\/a><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #000000;\"><strong>Figure 7.10. Long Chain Hydrocarbons are Insoluble in Water.\u00a0<\/strong>Neither<\/span><span style=\"color: #000000;\">\u00a0the saturated and unsaturated hydrocarbons in this sunflower oil do not have strong enough intermolecular forces to disrupt the hydrogen bonds\u00a0between the water molecules. Thus, the oil is not soluble in the water and forms beaded bubbles of oil at the surface of the water\/oil interface.\u00a0 In this case the oil is less dense than the water and will float on top of the water layer.<\/span><\/p>\n<div class=\"section\" id=\"gob-ch12_s02\" lang=\"en\">\n<h5 class=\"editable\"><span style=\"color: #ff0000;\"><em><strong>Solubility in organic solvents<\/strong><\/em><\/span><\/h5>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">In most organic solvents, the\u00a0primary forces of attraction between the solvent molecules are the\u00a0London dispersion\u00a0forces. Therefore, when an alkane dissolves in an organic solvent, the\u00a0London dispersion\u00a0forces\u00a0are broken and are replaced by new\u00a0London dispersion\u00a0forces between the mixture. The two processes more or less cancel each other out energetically; thus,\u00a0there is no barrier to solubility.<\/span><\/span><\/p>\n<h5 style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<hr \/>\n<h4 id=\"hazards\"><span style=\"color: #000000;\"><strong>Alkane Properties and Environmental Hazards: A Closer Look<\/strong><\/span><\/h4>\n<p class=\"title\"><span style=\"color: #000000;\">Due to the solubility and density of alkanes, oil spills into the ocean or other bodies of water can have devastating environmental consequences.\u00a0 The oil cannot dissolve or mix with the water, and because it is less dense than water, it floats on top of the surface of the water creating an oil slick, as depicted in Figure 7.11. Since the oil slick remains at the surface of the water, the organisms most affected by oil slicks are those found on the surface of the ocean or near the shorelines, including sea otters and seabirds. The chemical constituents of the oil are toxic though ingestion, inhalation, and through skin and eye irritation.<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" width=\"689\" height=\"939\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/72b9e9bbea354b72b7597ad3115f32ae.jpg\" \/><\/p>\n<p class=\"para\"><span style=\"color: #000000;\"><strong><span class=\"title-prefix\">Figure\u00a07.11<\/span> Oil Spills.<\/strong> Crude oil coats the water\u2019s surface in the Gulf of Mexico after the <em class=\"emphasis\">Deepwater Horizon<\/em> oil rig sank following an explosion. The leak was a mile below the surface, making it difficult to estimate the size of the spill. One liter of oil can create a slick 2.5 hectares (6.3 acres) in size. This and similar spills provide a reminder that hydrocarbons and water don\u2019t mix.<\/span><\/p>\n<div class=\"copyright\">\n<p class=\"para\"><span style=\"color: #000000;\">Source: Photo courtesy of <a href=\"http:\/\/www.nasa.gov\/topics\/earth\/features\/oilspill\/oil-20100519a.html\">NASA Goddard \/ MODIS Rapid Response Team<\/a>.<\/span><\/p>\n<div class=\"qandaset block\" id=\"gob-ch12_s06_qs01\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><strong><em>Concept Review Exercises<\/em><\/strong><\/span><\/h5>\n<ol class=\"qandadiv\" id=\"gob-ch12_s06_qs01_qd01\">\n<li class=\"qandaentry\" id=\"gob-ch12_s06_qs01_qd01_qa01\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s06_qs01_p01\"><span style=\"color: #000000;\">Without referring to a table, predict which has a higher boiling point\u2014hexane or dodecane. Explain.<\/span><\/p>\n<p class=\"para\"><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/hexane-vs-dodecane.png\"><img loading=\"lazy\" decoding=\"async\" width=\"446\" height=\"115\" class=\"alignnone wp-image-2606\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/hexane-vs-dodecane.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/hexane-vs-dodecane.png 826w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/hexane-vs-dodecane-300x77.png 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/hexane-vs-dodecane-768x198.png 768w\" sizes=\"(max-width: 446px) 100vw, 446px\" \/><\/a><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s06_qs01_qd01_qa02\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s06_qs01_p03\"><span style=\"color: #000000;\">If 25 mL of hexane were added to 100 mL of water in a beaker, which of the following would you expect to happen? Explain.<\/span><\/p>\n<ol class=\"orderedlist\" id=\"gob-ch12_s06_qs01_l01\">\n<li><span style=\"color: #000000;\">Hexane would dissolve in water.<\/span><\/li>\n<li><span style=\"color: #000000;\">Hexane would not dissolve in water and would float on top.<\/span><\/li>\n<li><span style=\"color: #000000;\">Hexane would not dissolve in water and would sink to the bottom of the container.<\/span><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div class=\"qandaset block\" id=\"gob-ch12_s06_qs01_ans\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><strong><em>Answers<\/em><\/strong><\/span><\/h5>\n<ol class=\"qandadiv\">\n<li class=\"qandaentry\" id=\"gob-ch12_s06_qs01_qd01_qa01_ans\">\n<div class=\"answer\">\n<p class=\"para\" id=\"gob-ch12_s06_qs01_p02_ans\"><span style=\"color: #000000;\">dodecane\u00a0because of its greater molar mass<\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s06_qs01_qd01_qa02_ans\">\n<div class=\"answer\">\n<p class=\"para\" id=\"gob-ch12_s06_qs01_p04_ans\"><span style=\"color: #000000;\">b; hexane is insoluble in water and less dense than water.<\/span><\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div class=\"key_takeaways editable block\" id=\"gob-ch12_s06_n05\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><em><strong>Key Takeaway<\/strong><\/em><\/span><\/h5>\n<ul class=\"itemizedlist\" id=\"gob-ch12_s06_l04\">\n<li><span style=\"color: #000000;\">Alkanes are nonpolar compounds that are low boiling and insoluble in water.<\/span><\/li>\n<\/ul>\n<\/div>\n<div class=\"qandaset block\" id=\"gob-ch12_s06_qs02\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><strong><em>Exercises<\/em><\/strong><\/span><\/h5>\n<ol class=\"qandadiv\" id=\"gob-ch12_s06_qs02_qd01\">\n<li class=\"qandaentry\" id=\"gob-ch12_s06_qs02_qd01_qa01\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s06_qs02_p01\"><span style=\"color: #000000;\">Without referring to a table or other reference, predict which member of each pair has the higher boiling point.<\/span><\/p>\n<ol class=\"orderedlist\" id=\"gob-ch12_s06_qs02_l01\">\n<li><span style=\"color: #000000;\">pentane or butane<a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/pentane-and-butane.png\"><img loading=\"lazy\" decoding=\"async\" width=\"221\" height=\"94\" class=\"wp-image-2607 aligncenter\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/pentane-and-butane.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/pentane-and-butane.png 417w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/pentane-and-butane-300x127.png 300w\" sizes=\"(max-width: 221px) 100vw, 221px\" \/><\/a><\/span><\/li>\n<li><span style=\"color: #000000;\">heptane or nonane<a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/heptane-and-nonane.png\"><img loading=\"lazy\" decoding=\"async\" width=\"313\" height=\"98\" class=\"wp-image-2608 aligncenter\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/heptane-and-nonane.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/heptane-and-nonane.png 600w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/heptane-and-nonane-300x94.png 300w\" sizes=\"(max-width: 313px) 100vw, 313px\" \/><\/a><\/span><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s06_qs02_qd01_qa02\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s06_qs02_p02\"><span style=\"color: #000000;\">For which member of each pair is hexane a good solvent?<\/span><\/p>\n<ol class=\"orderedlist\" id=\"gob-ch12_s06_qs02_l03\">\n<li><span style=\"color: #000000;\">pentane or water<\/span><\/li>\n<li><span style=\"color: #000000;\">sodium chloride or soybean oil<\/span><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div class=\"qandaset block\" id=\"gob-ch12_s06_qs02_ans\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><strong><em>Answer<\/em><\/strong><\/span><\/h5>\n<ol class=\"qandadiv\">\n<li class=\"qandaentry\" id=\"gob-ch12_s06_qs02_qd01_qa01_ans\">\n<div class=\"answer\">\n<ol class=\"orderedlist\" id=\"gob-ch12_s06_qs02_l02_ans\">\n<li><span style=\"color: #000000;\">pentane<\/span><\/li>\n<li><span style=\"color: #000000;\">nonane<\/span><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"mt-section\" id=\"section_8\">\n<hr \/>\n<h5 class=\"editable\" style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<h3 class=\"editable\" id=\"reactivity\"><strong><span style=\"color: #ff0000;\">7.4 Chemical Reactivity of Alkanes<\/span><\/strong><\/h3>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">Alkanes contain strong carbon-carbon single bonds and strong carbon-hydrogen bonds.\u00a0Both of these\u00a0bonds are nonpolar. Therefore, there is no portion of the molecule that\u00a0carries any significant amount of positive or negative charge, which is required for other ionic and polar molecules to be attracted to it. T<\/span><\/span><span style=\"color: #000000;\">herefore alkanes generally do not react with ionic compounds such as most laboratory acids, bases, oxidizing agents, or reducing agents. Consider butane as an example:<\/span><\/p>\n<div class=\"informalfigure large block\" id=\"fwk-gob-eq12_001\"><img loading=\"lazy\" decoding=\"async\" width=\"474\" height=\"128\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/66dc60cbec61ff3a93f93302145b5a72.jpg\" \/><\/div>\n<p class=\"para editable block\" id=\"gob-ch12_s07_p02\"><span style=\"color: #000000;\">Neither positive ions nor negative ions are attracted to a nonpolar molecule. In fact, the alkanes undergo so few reactions that they are sometimes called <strong><em class=\"emphasis\">paraffins<\/em><\/strong>, from the Latin <em class=\"emphasis\">parum affinis<\/em>, meaning \u201clittle affinity.\u201d<\/span><\/p>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">The\u00a0result is that alkanes have very little reactivity and only undergo three major types of reactions, including the following:<\/span><\/span><\/p>\n<ul>\n<li><span><span style=\"color: #000000; font-family: Helvetica,Arial;\"><strong>Combustion Reactions<\/strong> &#8211; burn them &#8211; destroying the\u00a0entire molecule;<\/span><\/span><\/li>\n<li><span><span style=\"color: #000000; font-family: Helvetica,Arial;\"><strong>Halogenation Reactions (substitution type)<\/strong>\u00a0&#8211; react them with some of the halogens, breaking the carbon-hydrogen bonds;<\/span><\/span><\/li>\n<li><span><span style=\"color: #000000; font-family: Helvetica,Arial;\"><strong>Cracking Reactions &#8211;<\/strong> use heat and\/or a catalyst to crack alkanes, breaking carbon-carbon bonds.<\/span><\/span><\/li>\n<\/ul>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">\u00a0<\/span><\/span><\/p>\n<hr \/>\n<h4 id=\"combustion\"><span style=\"color: #000000;\"><strong>Combustion Reactions<\/strong><\/span><\/h4>\n<p><span style=\"color: #000000;\">The combustion of carbon compounds, especially hydrocarbons, has been the most important source of heat energy for human civilizations throughout recorded history. The practical importance of this reaction cannot be denied, but the massive and uncontrolled chemical changes that take place in combustion make it difficult to deduce mechanistic paths. Using the combustion of propane as an example, we see from the following equation that every covalent bond in the reactants has been broken and an entirely new set of covalent bonds have formed in the products. No other common reaction involves such a profound and pervasive change, and the mechanism of combustion is so complex that chemists are just beginning to explore and understand some of its elementary features.<\/span><\/p>\n<div class=\"MathJax_Display\"><span class=\"MathJax MathJax_FullWidth\" id=\"MathJax-Element-1-Frame\" role=\"presentation\" style=\"color: #000000;\"><span class=\"math\" id=\"MathJax-Span-1\"><span class=\"mrow\" id=\"MathJax-Span-2\"><span class=\"mtable\" id=\"MathJax-Span-3\"><span class=\"mtd\" id=\"MathJax-Span-7\"><span class=\"mrow\" id=\"MathJax-Span-8\"><span class=\"msubsup\" id=\"MathJax-Span-9\"><span class=\"mtext\" id=\"MathJax-Span-10\">CH<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-14\"><span class=\"mrow\" id=\"MathJax-Span-15\"><span class=\"mn\" id=\"MathJax-Span-16\">3<\/span><\/span><\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-17\"><span class=\"mtext\" id=\"MathJax-Span-18\">CH<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-22\"><span class=\"mrow\" id=\"MathJax-Span-23\"><span class=\"mn\" id=\"MathJax-Span-24\">2<\/span><\/span><\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-25\"><span class=\"mtext\" id=\"MathJax-Span-26\">CH<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-30\"><span class=\"mrow\" id=\"MathJax-Span-31\"><span class=\"mn\" id=\"MathJax-Span-32\">3\u00a0 <\/span><\/span><\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-33\">+\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-34\">5<\/span><span class=\"msubsup\" id=\"MathJax-Span-35\"><span class=\"mtext\" id=\"MathJax-Span-36\">O<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-40\"><span class=\"mrow\" id=\"MathJax-Span-41\"><span class=\"mn\" id=\"MathJax-Span-42\">2\u00a0 <\/span><\/span><\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-43\">\u2192\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-44\">3<\/span><span class=\"msubsup\" id=\"MathJax-Span-45\"><span class=\"mtext\" id=\"MathJax-Span-46\">CO<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-50\"><span class=\"mrow\" id=\"MathJax-Span-51\"><span class=\"mn\" id=\"MathJax-Span-52\">2\u00a0 <\/span><\/span><\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-53\">+\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-54\">4<\/span><span class=\"msubsup\" id=\"MathJax-Span-55\"><span class=\"mtext\" id=\"MathJax-Span-56\">H<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-60\"><span class=\"mrow\" id=\"MathJax-Span-61\"><span class=\"mn\" id=\"MathJax-Span-62\">2<\/span><\/span><\/span><\/sub><\/span><span class=\"mtext\" id=\"MathJax-Span-63\">O\u00a0 <\/span><span class=\"mo\" id=\"MathJax-Span-64\">+\u00a0 <\/span><span class=\"mtext\" id=\"MathJax-Span-65\">heat<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/div>\n<\/div>\n<div class=\"mt-section\" id=\"section_8\">\n<p><span style=\"color: #000000;\">Note that in the reaction above, that the compounds on the left side of the arrow are called the <em>substrates or reactants<\/em> and the compounds on the right side of the arrow are the <em>products<\/em> of the reaction. Energy, most often released as heat, can either be a substrate or the product of the reaction, depending on the compounds involved. Also note that none of the atoms are lost within a given chemical equations.\u00a0 <em>The\u00a0Law of Conservation of Mass<\/em>\u00a0states that matter can neither be created or destroyed. Thus, the equation\u00a0must be balanced and have the same number of each atom on the\u00a0left side of the\u00a0equation as on the right. Recall that the coefficients of the equation determine how many moles of compound are present, and that if no coefficient is shown, it is one by default.\u00a0 For example, the equation above would be read as: 1 mole of propane (<span class=\"MathJax MathJax_FullWidth\" id=\"MathJax-Element-1-Frame\" role=\"presentation\" style=\"color: #000000;\"><span class=\"math\" id=\"MathJax-Span-1\"><span class=\"mrow\" id=\"MathJax-Span-2\"><span class=\"mtable\" id=\"MathJax-Span-3\"><span class=\"mtd\" id=\"MathJax-Span-7\"><span class=\"mrow\" id=\"MathJax-Span-8\"><span class=\"msubsup\" id=\"MathJax-Span-9\"><span class=\"mtext\" id=\"MathJax-Span-10\">CH<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-14\"><span class=\"mrow\" id=\"MathJax-Span-15\"><span class=\"mn\" id=\"MathJax-Span-16\">3<\/span><\/span><\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-17\"><span class=\"mtext\" id=\"MathJax-Span-18\">CH<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-22\"><span class=\"mrow\" id=\"MathJax-Span-23\"><span class=\"mn\" id=\"MathJax-Span-24\">2<\/span><\/span><\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-25\"><span class=\"mtext\" id=\"MathJax-Span-26\">CH<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-30\"><span class=\"mrow\" id=\"MathJax-Span-31\"><span class=\"mn\" id=\"MathJax-Span-32\">3<\/span><\/span><\/span><\/sub><\/span><\/span><\/span><\/span><\/span><\/span><\/span>) reacts with 5 moles of oxygen (<span class=\"msubsup\" id=\"MathJax-Span-35\"><span class=\"mtext\" id=\"MathJax-Span-36\">O<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-40\"><span class=\"mrow\" id=\"MathJax-Span-41\"><span class=\"mn\" id=\"MathJax-Span-42\">2<\/span><\/span><\/span><\/sub><\/span>) to produce 3 moles of carbon dioxide (<span class=\"msubsup\" id=\"MathJax-Span-45\"><span class=\"mtext\" id=\"MathJax-Span-46\">CO<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-50\"><span class=\"mrow\" id=\"MathJax-Span-51\"><span class=\"mn\" id=\"MathJax-Span-52\">2<\/span><\/span><\/span><\/sub><\/span>) and 4 moles of water (<span class=\"msubsup\" id=\"MathJax-Span-55\"><span class=\"mtext\" id=\"MathJax-Span-56\">H<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-60\"><span class=\"mrow\" id=\"MathJax-Span-61\"><span class=\"mn\" id=\"MathJax-Span-62\">2<\/span><\/span><\/span><\/sub><\/span><span class=\"mtext\" id=\"MathJax-Span-63\">O) and heat is released.<\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">Chemical bonds also hold potential energy.\u00a0 If you think about the nature of a bond, it is held together by the energy of attraction.\u00a0 To break apart bonds on the reactant side of the equation requires energy, while the formation of bonds on the product side will release energy.\u00a0 If the energy released by bond formation is higher than that\u00a0required for\u00a0bond dissociation, energy will be released by the reaction.<\/span> <span style=\"color: #000000;\">This energy is usually measured as heat of the reaction, which is called <em>enthalpy<\/em>.<\/span><\/p>\n<p><span style=\"color: #000000;\">Two points concerning this reaction are important:<\/span><\/p>\n<ol>\n<li><span style=\"color: #000000;\">Since all the covalent bonds in the reactant molecules are broken, the quantity of heat evolved in this reaction is related to the strength of these bonds (and, of course, the strength of the bonds formed in the products).\u00a0 These heats can be\u00a0evaluated\u00a0using the bond dissociation\/formation energies (the energy\u00a0required to break a bond on the\u00a0reactant-side of the equation\u00a0and the energy released by bond formation\u00a0on the product-side of the equation).\u00a0<\/span><\/li>\n<li><span style=\"color: #000000;\">The stoichiometry of the reactants is also\u00a0important. If insufficient oxygen is supplied some of the products will consist of the less oxidized carbon monoxide (<span class=\"MathJax\" id=\"MathJax-Element-2-Frame\" role=\"presentation\"><span class=\"math\" id=\"MathJax-Span-66\"><span class=\"mrow\" id=\"MathJax-Span-67\"><span class=\"mtext\" id=\"MathJax-Span-68\">CO)<\/span><\/span><\/span><\/span> gas.<\/span><\/li>\n<\/ol>\n<p class=\"MathJax_Display\"><span style=\"color: #000000;\">For example, if only 4 moles of oxygen was present, the combustion of one mole of propane would produce only 1 mole of carbon dioxide and 2 moles of carbon monoxide. <\/span><\/p>\n<div class=\"MathJax_Display\"><\/div>\n<div class=\"MathJax_Display\"><span class=\"MathJax MathJax_FullWidth\" id=\"MathJax-Element-3-Frame\" role=\"presentation\"><span class=\"math\" id=\"MathJax-Span-69\"><span class=\"mrow\" id=\"MathJax-Span-70\"><span class=\"mtable\" id=\"MathJax-Span-71\"><span class=\"mtd\" id=\"MathJax-Span-75\"><span class=\"mrow\" id=\"MathJax-Span-76\"><span class=\"msubsup\" id=\"MathJax-Span-77\"><span class=\"mtext\" id=\"MathJax-Span-78\">CH<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-82\"><span class=\"mrow\" id=\"MathJax-Span-83\"><span class=\"mn\" id=\"MathJax-Span-84\">3<\/span><\/span><\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-85\"><span class=\"mtext\" id=\"MathJax-Span-86\">CH<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-90\"><span class=\"mrow\" id=\"MathJax-Span-91\"><span class=\"mn\" id=\"MathJax-Span-92\">2<\/span><\/span><\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-93\"><span class=\"mtext\" id=\"MathJax-Span-94\">CH<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-98\"><span class=\"mrow\" id=\"MathJax-Span-99\"><span class=\"mn\" id=\"MathJax-Span-100\">3\u00a0 <\/span><\/span><\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-101\">+\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-102\">4<\/span><span class=\"msubsup\" id=\"MathJax-Span-103\"><span class=\"mtext\" id=\"MathJax-Span-104\">O<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-108\"><span class=\"mrow\" id=\"MathJax-Span-109\"><span class=\"mn\" id=\"MathJax-Span-110\">2\u00a0 <\/span><\/span><\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-111\">\u2192\u00a0 <\/span><span class=\"msubsup\" id=\"MathJax-Span-112\"><span class=\"mtext\" id=\"MathJax-Span-113\">CO<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-117\"><span class=\"mrow\" id=\"MathJax-Span-118\"><span class=\"mn\" id=\"MathJax-Span-119\">2\u00a0 <\/span><\/span><\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-120\">+\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-121\">2<\/span><span class=\"mtext\" id=\"MathJax-Span-122\">CO\u00a0 <\/span><span class=\"mo\" id=\"MathJax-Span-123\">+\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-124\">4<\/span><span class=\"msubsup\" id=\"MathJax-Span-125\"><span class=\"mtext\" id=\"MathJax-Span-126\">H<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-130\"><span class=\"mrow\" id=\"MathJax-Span-131\"><span class=\"mn\" id=\"MathJax-Span-132\">2<\/span><\/span><\/span><\/sub><\/span><span class=\"mtext\" id=\"MathJax-Span-133\">O\u00a0 <\/span><span class=\"mo\" id=\"MathJax-Span-134\">+\u00a0 <\/span><span class=\"mtext\" id=\"MathJax-Span-135\">heat<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/div>\n<\/div>\n<\/div>\n<div class=\"MathJax_Display\" style=\"text-align: right;\"><\/div>\n<div class=\"MathJax_Display\" style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/div>\n<div class=\"MathJax_Display\"><\/div>\n<div class=\"section\" id=\"gob-ch12_s02\" lang=\"en\">\n<div class=\"mt-section\" id=\"section_8\">\n<div class=\"mt-section\" id=\"section_1\">\n<hr \/>\n<h5><span style=\"color: #ff0000;\"><em>Bond Energies<\/em><\/span><\/h5>\n<p><span style=\"color: #000000;\">Atoms bond together to form compounds because in doing so they attain lower energies than they possess as individual atoms. A quantity of energy, equal to the difference between the energies of the bonded atoms and the energies of the separated atoms, is released, usually as heat. That is, the bonded atoms have a lower energy than the individual atoms have as separate atoms. <em class=\"emphasis\">When atoms combine to make a compound, energy is always given off, and the compound has a lower overall energy.<\/em><\/span><\/p>\n<p><span style=\"color: #000000;\">When a chemical reaction occurs, molecular bonds are broken and other bonds are formed to make different molecules. For example, the bonds of two water molecules are broken to form hydrogen and oxygen.\u00a0<\/span><\/p>\n<div class=\"MathJax_Display\"><span class=\"MathJax MathJax_FullWidth\" id=\"MathJax-Element-1-Frame\" role=\"presentation\"><span class=\"math\" id=\"MathJax-Span-1\"><span class=\"mrow\" id=\"MathJax-Span-2\"><span class=\"mtable\" id=\"MathJax-Span-3\"><span class=\"mtd\" id=\"MathJax-Span-7\"><span class=\"mrow\" id=\"MathJax-Span-8\"><span class=\"mn\" id=\"MathJax-Span-9\">2<\/span><span class=\"msubsup\" id=\"MathJax-Span-10\"><span class=\"mi\" id=\"MathJax-Span-11\">H<\/span><sub><span class=\"mn\" id=\"MathJax-Span-12\">2<\/span><\/sub><\/span><span class=\"mi\" id=\"MathJax-Span-13\">O\u00a0 <\/span><span class=\"mo\" id=\"MathJax-Span-14\">\u2192\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-15\">2<\/span><span class=\"msubsup\" id=\"MathJax-Span-16\"><span class=\"mi\" id=\"MathJax-Span-17\">H<\/span><sub><span class=\"mn\" id=\"MathJax-Span-18\">2\u00a0 <\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-19\">+\u00a0 <\/span><span class=\"msubsup\" id=\"MathJax-Span-20\"><span class=\"mi\" id=\"MathJax-Span-21\">O<\/span><sub><span class=\"mn\" id=\"MathJax-Span-22\">2<\/span><\/sub><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/div>\n<p><span style=\"color: #000000;\">Energy is always required\u00a0to break a bond, which is known as the\u00a0<em>bond energy<\/em>. While the concept may seem simple, bond energy serves a very important purpose in describing the structure and characteristics of a molecule. It can be used to determine which Lewis Dot Structure is most suitable when there are multiple Lewis Dot Structures.<\/span><\/p>\n<h5><span style=\"color: #ff0000;\"><em>Key Takeaways:<\/em><\/span><\/h5>\n<ul>\n<li><span style=\"color: #000000;\">\u00a0\u00a0 <em>Energy is always required\u00a0to break a bond. <\/em><\/span><\/li>\n<li><span style=\"color: #000000;\"><em>\u00a0\u00a0 Energy is always released when a bond is made.<\/em><\/span><\/li>\n<\/ul>\n<p><span style=\"color: #000000;\">Although each molecule has its own characteristic bond energy, some generalizations are possible. For example, although the exact value of a C\u2013H bond energy depends on the particular molecule, all C\u2013H bonds have a bond energy of roughly the same value because they are all C\u2013H bonds. It takes roughly 100 kcal of energy to break 1 mol of C\u2013H bonds, so we speak of the bond energy of a C\u2013H bond as being about 100 kcal\/mol. A C\u2013C bond has an approximate bond energy of 80 kcal\/mol, while a C=C has a bond energy of about 145 kcal\/mol. We can calculate a more general bond energy by finding the average of the bond energies of a specific bond in different molecules to get the average bond energy. Table 7.2 provides a list of average bond energies for common organic bonds. Remember that energy can be evaluated in kcal or kJ and that the conversion factor between the two is: \u00a04.184 kJ = 1 kcal<\/span><\/p>\n<table width=\"650\" align=\"center\" border=\"1\">\n<caption><span style=\"color: #000000;\"><strong><em>Table 7.4: Average Bond Energies (kJ\/mol)<\/em><\/strong><\/span><\/caption>\n<thead>\n<tr>\n<th style=\"width: 348.45px;\" colspan=\"6\" scope=\"col\">Single Bonds<\/th>\n<th style=\"width: 285.55px;\" colspan=\"2\" scope=\"col\">Multiple Bonds<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td style=\"width: 45.27px;\">H\u2014H<\/td>\n<td style=\"width: 48px;\">\n<div>432<\/div>\n<\/td>\n<td style=\"width: 45.27px;\">N\u2014H<\/td>\n<td style=\"width: 76.77px;\">\n<div>391<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">I\u2014I<\/td>\n<td style=\"width: 51.57px;\">\n<div>149<\/div>\n<\/td>\n<td style=\"width: 57.87px;\">C = C<\/td>\n<td style=\"width: 221.68px;\">\n<div>614<\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">H\u2014F<\/td>\n<td style=\"width: 48px;\">\n<div>565<\/div>\n<\/td>\n<td style=\"width: 45.27px;\">N\u2014N<\/td>\n<td style=\"width: 76.77px;\">\n<div>160<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">I\u2014Cl<\/td>\n<td style=\"width: 51.57px;\">\n<div>208<\/div>\n<\/td>\n<td style=\"width: 57.87px;\">C \u2261 C<\/td>\n<td style=\"width: 221.68px;\">\n<div>839<\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">H\u2014Cl<\/td>\n<td style=\"width: 48px;\">\n<div>427<\/div>\n<\/td>\n<td style=\"width: 45.27px;\">N\u2014F<\/td>\n<td style=\"width: 76.77px;\">\n<div>272<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">I\u2014Br<\/td>\n<td style=\"width: 51.57px;\">\n<div>175<\/div>\n<\/td>\n<td style=\"width: 57.87px;\">O = O<\/td>\n<td style=\"width: 221.68px;\">\n<div>495<\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">H\u2014Br<\/td>\n<td style=\"width: 48px;\">\n<div>363<\/div>\n<\/td>\n<td style=\"width: 45.27px;\">N\u2014Cl<\/td>\n<td style=\"width: 76.77px;\">\n<div>200<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">\n<div><\/div>\n<\/td>\n<td style=\"width: 51.57px;\">C = O*<\/td>\n<td style=\"width: 57.87px;\">\n<div>745<\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">H\u2014I<\/td>\n<td style=\"width: 48px;\">\n<div>295<\/div>\n<\/td>\n<td style=\"width: 45.27px;\">N\u2014Br<\/td>\n<td style=\"width: 76.77px;\">\n<div>243<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">S\u2014H<\/td>\n<td style=\"width: 51.57px;\">\n<div>347<\/div>\n<\/td>\n<td style=\"width: 57.87px;\">C \u2261 O<\/td>\n<td style=\"width: 221.68px;\">\n<div>1072<\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">\n<div><\/div>\n<\/td>\n<td style=\"width: 48px;\">N\u2014O<\/td>\n<td style=\"width: 45.27px;\">\n<div>201<\/div>\n<\/td>\n<td style=\"width: 76.77px;\">S\u2014F<\/td>\n<td style=\"width: 51.57px;\">\n<div>327<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">N = O<\/td>\n<td style=\"width: 57.87px;\">\n<div>607<\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">C\u2014H<\/td>\n<td style=\"width: 48px;\">\n<div>413<\/div>\n<\/td>\n<td style=\"width: 45.27px;\">O\u2014H<\/td>\n<td style=\"width: 76.77px;\">\n<div>467<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">S\u2014Cl<\/td>\n<td style=\"width: 51.57px;\">\n<div>253<\/div>\n<\/td>\n<td style=\"width: 57.87px;\">N = N<\/td>\n<td style=\"width: 221.68px;\">\n<div>418<\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">C\u2014C<\/td>\n<td style=\"width: 48px;\">\n<div>347<\/div>\n<\/td>\n<td style=\"width: 45.27px;\">O\u2014O<\/td>\n<td style=\"width: 76.77px;\">\n<div>146<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">S\u2014Br<\/td>\n<td style=\"width: 51.57px;\">\n<div>218<\/div>\n<\/td>\n<td style=\"width: 57.87px;\">N \u2261 N<\/td>\n<td style=\"width: 221.68px;\">\n<div>941<\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">C\u2014N<\/td>\n<td style=\"width: 48px;\">\n<div>305<\/div>\n<\/td>\n<td style=\"width: 45.27px;\">O\u2014F<\/td>\n<td style=\"width: 76.77px;\">\n<div>190<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">S\u2014S<\/td>\n<td style=\"width: 51.57px;\">\n<div>266<\/div>\n<\/td>\n<td style=\"width: 57.87px;\">C \u2261 N<\/td>\n<td style=\"width: 221.68px;\">\n<div>891<\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">C\u2014O<\/td>\n<td style=\"width: 48px;\">\n<div>358<\/div>\n<\/td>\n<td style=\"width: 45.27px;\">O\u2014Cl<\/td>\n<td style=\"width: 76.77px;\">\n<div>203<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">\n<div><\/div>\n<\/td>\n<td style=\"width: 51.57px;\">C = N<\/td>\n<td style=\"width: 57.87px;\">\n<div>615<\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">C\u2014F<\/td>\n<td style=\"width: 48px;\">\n<div>485<\/div>\n<\/td>\n<td style=\"width: 45.27px;\">O\u2014I<\/td>\n<td style=\"width: 76.77px;\">\n<div>234<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">Si\u2014Si<\/td>\n<td style=\"width: 51.57px;\">\n<div>340<\/div>\n<\/td>\n<td style=\"width: 57.87px;\">\n<div><\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">C\u2014Cl<\/td>\n<td style=\"width: 48px;\">\n<div>339<\/div>\n<\/td>\n<td style=\"width: 45.27px;\">\n<div><\/div>\n<\/td>\n<td style=\"width: 76.77px;\">Si\u2014H<\/td>\n<td style=\"width: 51.57px;\">\n<div>393<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">\n<div><\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">C\u2014Br<\/td>\n<td style=\"width: 48px;\">\n<div>276<\/div>\n<\/td>\n<td style=\"width: 45.27px;\">F\u2014F<\/td>\n<td style=\"width: 76.77px;\">\n<div>154<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">Si\u2014C<\/td>\n<td style=\"width: 51.57px;\">\n<div>360<\/div>\n<\/td>\n<td style=\"width: 57.87px;\">\n<div><\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">C\u2014I<\/td>\n<td style=\"width: 48px;\">\n<div>240<\/div>\n<\/td>\n<td style=\"width: 45.27px;\">F\u2014Cl<\/td>\n<td style=\"width: 76.77px;\">\n<div>253<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">Si\u2014O<\/td>\n<td style=\"width: 51.57px;\">\n<div>452<\/div>\n<\/td>\n<td style=\"width: 57.87px;\">\n<div><\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">C\u2014S<\/td>\n<td style=\"width: 48px;\">\n<div>259<\/div>\n<\/td>\n<td style=\"width: 45.27px;\">F\u2014Br<\/td>\n<td style=\"width: 76.77px;\">\n<div>237<\/div>\n<\/td>\n<td style=\"width: 51.57px;\">\n<div><\/div>\n<\/td>\n<td style=\"width: 51.57px;\">\n<div><\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">\n<div><\/div>\n<\/td>\n<td style=\"width: 48px;\">Cl\u2014Cl<\/td>\n<td style=\"width: 45.27px;\">\n<div>239<\/div>\n<\/td>\n<td style=\"width: 76.77px;\">\n<div><\/div>\n<\/td>\n<td style=\"width: 51.57px;\">\n<div><\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">\n<div><\/div>\n<\/td>\n<td style=\"width: 48px;\">Cl\u2014Br<\/td>\n<td style=\"width: 45.27px;\">\n<div>218<\/div>\n<\/td>\n<td style=\"width: 76.77px;\">\n<div><\/div>\n<\/td>\n<td style=\"width: 51.57px;\">\n<div><\/div>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 45.27px;\">\n<div><\/div>\n<\/td>\n<td style=\"width: 48px;\">Br\u2014Br<\/td>\n<td style=\"width: 45.27px;\">\n<div>193<\/div>\n<\/td>\n<td style=\"width: 76.77px;\">\n<div><\/div>\n<\/td>\n<td style=\"width: 51.57px;\">\n<div><\/div>\n<\/td>\n<\/tr>\n<tr>\n<td align=\"right\" style=\"width: 640px;\" colspan=\"8\">\n<div align=\"left\">*C\u00a0<span style=\"font-size: xx-small;\">=<\/span> O in (CO<sub>2<\/sub>) = 799<\/div>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><span style=\"color: #000000;\">When a bond is strong, there is a higher bond energy because it takes more energy to break a strong bond. This correlates with bond order and bond length. When the Bond order is higher, bond length is shorter, and the shorter the bond length means a greater the Bond Energy because of increased electric attraction. In general,\u00a0the shorter the bond length, the greater the bond energy.<\/span><\/p>\n<hr \/>\n<div class=\"mt-section\" id=\"section_1\">\n<h5 class=\"editable\"><span style=\"color: #ff0000;\"><em>Bond Breakage and Formation<\/em><\/span><\/h5>\n<p><span style=\"color: #000000;\">When a chemical reaction occurs, the atoms in the reactants rearrange their chemical bonds to make products. The new arrangement of bonds does not have the same total energy as the bonds in the reactants. Therefore, when chemical reactions occur, <em class=\"emphasis\">there will always be an accompanying energy change<\/em>. The energy change of a reaction or the heat of the reaction is called <em>enthalpy<\/em>. It is represented by the mathematical symbol, \u0394H, and is calculated as the difference of the energy required to break the bonds\u00a0of the reactants\u00a0minus the\u00a0energy released by the formation of the bonds in the\u00a0products.\u00a0\u00a0<\/span><\/p>\n<p style=\"text-align: center;\"><strong><span style=\"color: #000000;\">\u0394H = Energy of Reactants &#8211; Energy of Products<\/span><\/strong><\/p>\n<p><img decoding=\"async\" class=\"internal\" alt=\"\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/100066\/7_(2).jpg?revision=1\" \/><img decoding=\"async\" class=\"internal\" alt=\"\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/100067\/7_(1).jpg?revision=1\" \/><\/p>\n<p><span style=\"color: #000000;\"><strong>Figure 7.12: Reaction Enthalpy.\u00a0\u00a0<\/strong>(upper reaction) Exothermic Reactions. For an exothermic chemical reaction, energy is given off as reactants are converted to products.\u00a0(lower reaction)\u00a0Endothermic Reactions. For an endothermic chemical reaction, energy is absorbed as reactants are converted to products.<\/span><\/p>\n<hr \/>\n<p><span style=\"color: #000000;\">In some reactions, the energy of the resulting\u00a0products is lower than the energy of the reactants. Thus, in the course of the reaction, the\u00a0excess\u00a0energy released by product formation will be released\u00a0to the surrounding environment. Such reactions are exothermic and can be represented by an <em class=\"emphasis\">energy-level diagram<\/em> in Figure\u00a07.12 (upper). In most cases, the energy is given off as heat (although a few reactions give off energy as light). In chemical reactions where the products have a higher energy than the reactants, the reactants must absorb energy from their environment to be able to react. These reactions are endothermic and can be represented by an energy-level diagrams like Figure\u00a07.12 (lower).<\/span><\/p>\n<p><span style=\"color: #000000;\">Exothermic and endothermic reactions can be thought of as having energy as either a &#8220;product&#8221; of the reaction or a &#8220;reactant&#8221;, respectively. \u00a0Exothermic reactions release energy, so energy is a product. Endothermic reactions require energy, so energy is a reactant.<\/span><\/p>\n<p><span style=\"color: #000000;\">Exothermic reactions will have a negative overall enthalpy and endothermic reactions will have a positive overall enthalpy.<\/span><\/p>\n<p style=\"text-align: center;\"><strong><span style=\"color: #000000;\">\u0394H = Energy of Reactants &#8211; Energy of Products<\/span><\/strong><\/p>\n<div>\n<div id=\"example\">\n<p class=\"boxtitle\"><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/exothermic-and-endothermic.png\"><img loading=\"lazy\" decoding=\"async\" width=\"591\" height=\"318\" class=\"alignnone wp-image-2513\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/exothermic-and-endothermic-1024x551.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/exothermic-and-endothermic-1024x551.png 1024w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/exothermic-and-endothermic-300x161.png 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/exothermic-and-endothermic-768x413.png 768w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/exothermic-and-endothermic.png 1047w\" sizes=\"(max-width: 591px) 100vw, 591px\" \/><\/a><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/calculating-bond-energies.png\"><img loading=\"lazy\" decoding=\"async\" width=\"596\" height=\"309\" class=\"alignnone wp-image-2517\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/calculating-bond-energies-1024x532.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/calculating-bond-energies-1024x532.png 1024w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/calculating-bond-energies-300x156.png 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/calculating-bond-energies-768x399.png 768w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/calculating-bond-energies.png 1047w\" sizes=\"(max-width: 596px) 100vw, 596px\" \/><\/a><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/calculating-bond-energies-2.png\"><img loading=\"lazy\" decoding=\"async\" width=\"600\" height=\"778\" class=\"alignnone wp-image-2522\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/calculating-bond-energies-2-790x1024.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/calculating-bond-energies-2-790x1024.png 790w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/calculating-bond-energies-2-231x300.png 231w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/calculating-bond-energies-2-768x995.png 768w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/calculating-bond-energies-2.png 1061w\" sizes=\"(max-width: 600px) 100vw, 600px\" \/><\/a><\/p>\n<p><span style=\"color: #000000;\">The energy of a reaction can be treated stoichiometrically within the reaction just like any of the compounds within the reaction.\u00a0 For the combustion of methane, CH<sub>4<\/sub>, each mole that is burned will release 824 kJ of energy.\u00a0 Thus, it is easy to calculate how much energy is released for any amount of CH<sub>4<\/sub> that is burned. We can also easily calculate how much CO<sub>2<\/sub> is produced for each mole of CH<sub>4<\/sub> that is burned, since one mole of CO<sub>2<\/sub> is produced for each mole of CH<sub>4<\/sub> burned.<\/span><\/p>\n<h5 style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<hr \/>\n<\/div>\n<div>\n<div id=\"exercise\">\n<h5 class=\"boxtitle\"><span style=\"color: #ff0000;\"><em>Complete Combustion<\/em><\/span><\/h5>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p><span style=\"color: #000000; font-family: Helvetica,Arial;\">Complete combustion (given sufficient oxygen) of any hydrocarbon produces <em>carbon dioxide (CO<sub>2<\/sub>)<\/em>\u00a0and <em>water (H<sub>2<\/sub>O)<\/em>. It is quite important that you can write properly balanced equations for these reactions, because they often come up as a part of thermochemistry calculations. Some are easier than others. For example, with alkanes, the ones with an even number of carbon atoms are marginally harder than those with an odd number!<\/span><\/p>\n<div>\n<div id=\"example\">\n<p class=\"boxtitle\"><span style=\"color: #000000;\">Example 1: Propane Combustion<\/span><\/p>\n<p><span style=\"color: #000000; font-family: Helvetica,Arial;\">For example, with propane (C<sub>3<\/sub>H<sub>8<\/sub>), you can balance the carbons and hydrogens as you write the equation down. Your first draft would be:<\/span><\/p>\n<div class=\"MathJax_Display\"><span class=\"MathJax\" id=\"MathJax-Element-1-Frame\" role=\"presentation\"><span class=\"math\" id=\"MathJax-Span-1\"><span class=\"mrow\" id=\"MathJax-Span-2\"><span class=\"msubsup\" id=\"MathJax-Span-3\"><span class=\"mi\" id=\"MathJax-Span-4\">C<\/span><sub><span class=\"mn\" id=\"MathJax-Span-5\">3<\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-6\"><span class=\"mi\" id=\"MathJax-Span-7\">H<\/span><sub><span class=\"mn\" id=\"MathJax-Span-8\">8 \u00a0<\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-9\">+\u00a0 <span style=\"text-decoration: underline;\"><span style=\"color: #ff0000; text-decoration: underline;\">?<\/span><\/span><\/span><span style=\"text-decoration: underline;\"><span class=\"msubsup\" id=\"MathJax-Span-10\" style=\"color: #ff0000; text-decoration: underline;\"><span class=\"mi\" id=\"MathJax-Span-11\">O<\/span><sub><span class=\"mn\" id=\"MathJax-Span-12\">2\u00a0 <\/span><\/sub><\/span><\/span><span class=\"mo\" id=\"MathJax-Span-13\">\u2192\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-14\">3<\/span><span class=\"mi\" id=\"MathJax-Span-15\">C<\/span><span class=\"msubsup\" id=\"MathJax-Span-16\"><span class=\"mi\" id=\"MathJax-Span-17\">O<\/span><sub><span class=\"mn\" id=\"MathJax-Span-18\">2\u00a0 <\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-19\">+\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-20\">4<\/span><span class=\"msubsup\" id=\"MathJax-Span-21\"><span class=\"mi\" id=\"MathJax-Span-22\">H<\/span><sub><span class=\"mn\" id=\"MathJax-Span-23\">2<\/span><\/sub><\/span><span class=\"mi\" id=\"MathJax-Span-24\">O<\/span><\/span><\/span><\/span><\/div>\n<p><span style=\"color: #000000; font-family: Helvetica,Arial;\">Counting the oxygens leads directly to the final version:<\/span><\/p>\n<div class=\"MathJax_Display\"><span class=\"MathJax\" id=\"MathJax-Element-2-Frame\" role=\"presentation\"><span class=\"math\" id=\"MathJax-Span-25\"><span class=\"mrow\" id=\"MathJax-Span-26\"><span class=\"msubsup\" id=\"MathJax-Span-27\"><span class=\"mi\" id=\"MathJax-Span-28\">C<\/span><sub><span class=\"mn\" id=\"MathJax-Span-29\">3<\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-30\"><span class=\"mi\" id=\"MathJax-Span-31\">H<\/span><sub><span class=\"mn\" id=\"MathJax-Span-32\">8\u00a0 <\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-33\">+\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-34\">5<\/span><span class=\"msubsup\" id=\"MathJax-Span-35\"><span class=\"mi\" id=\"MathJax-Span-36\">O<\/span><sub><span class=\"mn\" id=\"MathJax-Span-37\">2\u00a0 <\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-38\">\u2192\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-39\">3<\/span><span class=\"mi\" id=\"MathJax-Span-40\">C<\/span><span class=\"msubsup\" id=\"MathJax-Span-41\"><span class=\"mi\" id=\"MathJax-Span-42\">O<\/span><sub><span class=\"mn\" id=\"MathJax-Span-43\">2\u00a0 <\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-44\">+\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-45\">4<\/span><span class=\"msubsup\" id=\"MathJax-Span-46\"><span class=\"mi\" id=\"MathJax-Span-47\">H<\/span><sub><span class=\"mn\" id=\"MathJax-Span-48\">2<\/span><\/sub><\/span><span class=\"mi\" id=\"MathJax-Span-49\">O<\/span><\/span><\/span><\/span><\/div>\n<div class=\"MathJax_Display\"><\/div>\n<\/div>\n<\/div>\n<div>\n<div id=\"example\">\n<p class=\"boxtitle\"><span style=\"color: #000000;\">Example 2: Butane Combustion<\/span><\/p>\n<p><span style=\"color: #000000; font-family: Helvetica,Arial;\">With butane (C<sub>4<\/sub>H<sub>10<\/sub>), you can again balance the carbons and hydrogens as you write the equation down.<\/span><\/p>\n<div class=\"MathJax_Display\"><span class=\"MathJax\" id=\"MathJax-Element-3-Frame\" role=\"presentation\"><span class=\"math\" id=\"MathJax-Span-50\"><span class=\"mrow\" id=\"MathJax-Span-51\"><span class=\"msubsup\" id=\"MathJax-Span-52\"><span class=\"mi\" id=\"MathJax-Span-53\">C<\/span><sub><span class=\"mn\" id=\"MathJax-Span-54\">4<\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-55\"><span class=\"mi\" id=\"MathJax-Span-56\">H<\/span><\/span><sub><span class=\"msubsup\" id=\"MathJax-Span-55\"><span class=\"texatom\" id=\"MathJax-Span-57\"><span class=\"mrow\" id=\"MathJax-Span-58\"><span class=\"mn\" id=\"MathJax-Span-59\">10\u00a0 <\/span><\/span><\/span><\/span><\/sub><span class=\"mo\" id=\"MathJax-Span-60\">+\u00a0\u00a0 <span style=\"text-decoration: underline;\"><span style=\"color: #ff0000; text-decoration: underline;\">?<\/span><\/span><\/span><span class=\"msubsup\" id=\"MathJax-Span-61\"><span style=\"text-decoration: underline;\"><span class=\"mi\" id=\"MathJax-Span-62\" style=\"color: #ff0000; text-decoration: underline;\">O<\/span><\/span><sub><span class=\"mn\" id=\"MathJax-Span-63\"><span style=\"text-decoration: underline;\"><span style=\"color: #ff0000; text-decoration: underline;\">2<\/span><\/span>\u00a0\u00a0 <\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-64\">\u2192\u00a0\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-65\">4<\/span><span class=\"mi\" id=\"MathJax-Span-66\">C<\/span><span class=\"msubsup\" id=\"MathJax-Span-67\"><span class=\"mi\" id=\"MathJax-Span-68\">O<\/span><sub><span class=\"mn\" id=\"MathJax-Span-69\">2\u00a0\u00a0 <\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-70\">+\u00a0\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-71\">5<\/span><span class=\"msubsup\" id=\"MathJax-Span-72\"><span class=\"mi\" id=\"MathJax-Span-73\">H<\/span><sub><span class=\"mn\" id=\"MathJax-Span-74\">2<\/span><\/sub><\/span><span class=\"mi\" id=\"MathJax-Span-75\">O<\/span><\/span><\/span><\/span><\/div>\n<p><span style=\"color: #000000; font-family: Helvetica,Arial;\">Counting the oxygens leads to a slight problem &#8211; with 13 on the right-hand side. Having an odd number of oxygens on the product side makes it impossible to balance with the even number on the reactant side.\u00a0 In cases like this, start trying to balance the equation, by changing the cofactor in front of the alkane to 2.\u00a0\u00a0Then rebalance the carbon and hydrogens on the product side. In this case, the oxygen number should come out to a positive number and you should now be able to balance the equation.<\/span><\/p>\n<div class=\"MathJax_Display\"><span class=\"MathJax\" id=\"MathJax-Element-5-Frame\" role=\"presentation\" style=\"color: #000000;\"><span class=\"math\" id=\"MathJax-Span-109\"><span class=\"mrow\" id=\"MathJax-Span-110\"><span class=\"mn\" id=\"MathJax-Span-111\">2<\/span><span class=\"msubsup\" id=\"MathJax-Span-112\"><span class=\"mi\" id=\"MathJax-Span-113\">C<\/span><sub><span class=\"mn\" id=\"MathJax-Span-114\">4<\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-115\"><span class=\"mi\" id=\"MathJax-Span-116\">H<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-117\"><span class=\"mrow\" id=\"MathJax-Span-118\"><span class=\"mn\" id=\"MathJax-Span-119\">10\u00a0\u00a0 <\/span><\/span><\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-120\">+\u00a0\u00a0 <\/span><span style=\"text-decoration: underline;\"><span style=\"color: #ff0000; text-decoration: underline;\"><span class=\"mn\" id=\"MathJax-Span-121\">13<\/span><span class=\"msubsup\" id=\"MathJax-Span-122\"><span class=\"mi\" id=\"MathJax-Span-123\">O<\/span><sub><span class=\"mn\" id=\"MathJax-Span-124\">2<\/span><\/sub><\/span><\/span><\/span><span style=\"color: #ff0000;\"><span class=\"msubsup\" id=\"MathJax-Span-122\"><span class=\"mn\" id=\"MathJax-Span-124\">\u00a0\u00a0\u00a0 <\/span><\/span><\/span><span class=\"mo\" id=\"MathJax-Span-125\">\u2192\u00a0\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-126\">8<\/span><span class=\"mi\" id=\"MathJax-Span-127\">C<\/span><span class=\"msubsup\" id=\"MathJax-Span-128\"><span class=\"mi\" id=\"MathJax-Span-129\">O<\/span><sub><span class=\"mn\" id=\"MathJax-Span-130\">2\u00a0\u00a0 <\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-131\">+\u00a0\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-132\">10<\/span><span class=\"msubsup\" id=\"MathJax-Span-133\"><span class=\"mi\" id=\"MathJax-Span-134\">H<\/span><sub><span class=\"mn\" id=\"MathJax-Span-135\">2<\/span><\/sub><\/span><span class=\"mi\" id=\"MathJax-Span-136\">O<\/span><\/span><\/span><\/span><\/div>\n<\/div>\n<\/div>\n<p><span style=\"color: #000000; font-family: Helvetica,Arial;\">The hydrocarbons become harder to ignite as the molecules get bigger. This is because the bigger molecules don&#8217;t vaporize so easily &#8211; the reaction is much better if the oxygen and the hydrocarbon are well mixed as gases. If the liquid is not very volatile, only those molecules on the surface can react with the oxygen. Bigger molecules have greater Van der Waals attractions which makes it more difficult for them to break away from their neighbors and turn to a gas.<\/span><\/p>\n<p><span style=\"color: #000000; font-family: Helvetica,Arial;\">Provided the combustion is complete, all the hydrocarbons will burn with a blue flame. However, combustion tends to be less complete as the number of carbon atoms in the molecules rises. That means that the bigger the hydrocarbon, the more likely you are to get a yellow, smoky flame.<\/span><\/p>\n<hr \/>\n<div class=\"mt-section\" id=\"section_2\">\n<h5 class=\"editable\"><span style=\"color: #ff0000;\"><em>Incomplete combustion<\/em><\/span><\/h5>\n<p><span style=\"color: #000000; font-family: Helvetica,Arial;\">Incomplete combustion (where there is not enough oxygen present) can lead to the formation of carbon or carbon monoxide. As a simple way of thinking about it, the hydrogen in the hydrocarbon gets the first chance at the oxygen to form water in the product, and the carbon gets whatever is left over! When only carbon is formed, the presence of glowing carbon particles in a flame turns it yellow, and black carbon is often visible in the smoke. If some oxygen can interact with the carbon, but not enough to form carbon dioxide (CO<sub>2<\/sub>), then carbon monoxide (CO)\u00a0is produced as a colorless poisonous gas.<\/span><\/p>\n<p><span style=\"color: #000000; font-family: Helvetica,Arial;\">Why carbon monoxide is poisonous<\/span>: <span style=\"color: #000000; font-family: Helvetica,Arial;\">Oxygen is carried around the blood by hemoglobin, a protein found in red blood cells. Carbon dioxide also binds with hemoglobin.\u00a0 Hemoglobin carries oxygen from your lungs to\u00a0every cell in your body, where it drops off the oxygen and picks up carbon dioxide and carries it back to the lungs.\u00a0 Hemoglobin will then exchange the carbon dioxide for the oxygen in the air that you breath in.\u00a0 When you exhale, you release the carbon dioxide. Carbon monoxide can also bind to hemoglobin.\u00a0 The difference is that carbon monoxide binds irreversibly (or very strongly) &#8211; making that particular molecule of hemoglobin useless for carrying oxygen. If you breath in enough carbon monoxide you will die from an internal form of suffocation!<\/span><\/p>\n<hr \/>\n<h5><span style=\"color: #ff0000;\"><i>Heat of Combustion<\/i><\/span><\/h5>\n<p><span style=\"color: #000000;\">The heat of combustion, \u0394H<sub>c <\/sub>, is defined as\u00a0the total energy released as heat when a substance undergoes complete combustion with oxygen under a set of standard conditions. It is calculated the same way that enthalpy is calculated, however, it is specific for a set of standard conditions.\u00a0 Heat of Combustion is a useful value because it is\u00a0a constant value\u00a0for the type of material being burned and can be used to compare the efficiency and utility of different fuel sources used most often in society (oil, gasoline, natural gas, diesel, coal, wood, hydrogen, ethanol, etc).\u00a0In the\u00a0United States, heating ratings\u00a0are commonly given in\u00a0 British Thermal Units (BTU) per pound\u00a0of material.\u00a0 A common conversion to the metric units is:<\/span><\/p>\n<p style=\"text-align: center;\"><strong><span style=\"color: #000000;\">BTU\/lb\u00a0 =\u00a0 (kJ\/kg)*2.326<\/span><\/strong><\/p>\n<p><span style=\"color: #000000;\">Heat of combustion, \u0394Hc, values common fuel sources and their associated CO2 emissions\u00a0are indicated in Table 7.5<\/span><\/p>\n<h5><span style=\"color: #000000;\"><strong>Table 7.5 Heat of Combustion and CO2 Emissions Profile of Common Fuels<\/strong><\/span><\/h5>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/energy_of_fuels_final.png\"><img loading=\"lazy\" decoding=\"async\" width=\"689\" height=\"495\" class=\"alignnone wp-image-2632\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/energy_of_fuels_final-1024x735.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/energy_of_fuels_final-1024x735.png 1024w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/energy_of_fuels_final-300x215.png 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/energy_of_fuels_final-768x551.png 768w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/energy_of_fuels_final.png 1339w\" sizes=\"(max-width: 689px) 100vw, 689px\" \/><\/a><\/p>\n<p><span style=\"color: #000000;\">Adapted from<\/span>: <a href=\"https:\/\/www.epa.gov\/sites\/production\/files\/2015-07\/documents\/emission-factors_2014.pdf\">EPA\u00a0-(2014)<\/a> <span style=\"color: #000000;\">and<\/span> <a href=\"https:\/\/en.wikipedia.org\/wiki\/Heat_of_combustion\">Wikipedia &#8211; Heat of Combustion<\/a><\/p>\n<hr \/>\n<p><span style=\"color: #000000;\"><em>Petroleum<\/em> (from Greek: <span lang=\"el\" xml:lang=\"el\">petra<\/span>: &#8220;rock&#8221; + <i>oleum<\/i>: &#8220;oil&#8221;) is a naturally occurring, yellow-to-black liquid found in geological formations beneath the Earth&#8217;s surface, which is commonly refined into various types of fuels. It consists\u00a0mainly\u00a0of alkanes, cycloalkanes, and alkenes of various\u00a0lengths and some\u00a0additional minor\u00a0organic compounds. Alkanes with five or more carbons are liquids and are found as common components of petroleum (also called <em>crude oil<\/em>). Many cycloalkanes are\u00a0also found in petroleum products as well including,\u00a0gasoline, kerosene, diesel, motor oil and many other heavy oils. Natural gas, on the other hand, is composed predominantly of methane (CH<sub><span style=\"font-size: small;\">4<\/span><\/sub>), but also contains ethane (C<sub><span style=\"font-size: small;\">2<\/span><\/sub>H<sub><span style=\"font-size: small;\">6<\/span><\/sub>), propane (C<sub><span style=\"font-size: small;\">3<\/span><\/sub>H<sub><span style=\"font-size: small;\">8<\/span><\/sub>), and butane (C<sub><span style=\"font-size: small;\">4<\/span><\/sub>H<sub><span style=\"font-size: small;\">10<\/span><\/sub>). Natural gas also contains trace levels of nitrogen, carbon dioxide (CO<sub><span style=\"font-size: small;\">2<\/span><\/sub>), and hydrogen sulfide (H<sub><span style=\"font-size: small;\">2<\/span><\/sub>S).<\/span><\/p>\n<p><span style=\"color: #000000;\">Components of petroleum are separated by size using a technique called fractional distillation. The resulting samples include gasoline with alkanes\u00a0ranging from\u00a0five to ten carbons in length and\u00a0kerosene\u00a0with a mixture of alkanes ranging in carbon length from ten to seventeen.\u00a0 Alkanes with longer carbon chains are found in diesel fuel, fuel oil, petroleum jelly, paraffin wax, motor oils, and the very highest chain length are used in asphalt.\u00a0 It is estimated that the world uses about 95 million barrels of oil each day! The <a href=\"https:\/\/www.epa.gov\/energy\/greenhouse-gases-equivalencies-calculator-calculations-and-references\">Environmental Protection Agency<\/a> estimates that each barrel of oil produces 0.43 metric tons of CO<sub>2<\/sub>.\u00a0Note that a\u00a0metric ton is equivalent to 1,000 kg.\u00a0That means that 40,850,000 metric tons of CO<sub>2<\/sub>\u00a0or 40,850,000,000 kg of CO<sub>2<\/sub> are released into the atmosphere each day just from oil consumption! That is almost 15 billion metric tons of CO<sub>2<\/sub> per year! This calculation only includes the\u00a0consumption of crude oil and not other common fuel sources, such as natural gas, coal, wood, and\u00a0renewable energy sources like ethanol and biodiesel.<\/span><\/p>\n<h5><span style=\"color: #ff0000;\"><em><strong>Up For Discussion:<\/strong><\/em><\/span><\/h5>\n<p><span style=\"color: #000000;\">In Oregon, it is estimated that\u00a0during the\u00a0winter months\u00a0that it take about 40 BTU per hour per square foot to heat an average, well-insulated home. If you owned a 2,000 square foot home, how many BTUs would you require to heat your own for 1 month? (assume 31 days in the month). If you had the choice of heating your house with natural gas, coal (lignite), or wood, how many kg of each of these fuels would be required to heat your home for one month?\u00a0 How much CO2 would be produced by each fuel each winter month?<\/span><\/p>\n<h5 style=\"text-align: right;\"><span style=\"color: #000000;\">\u00a0<span style=\"color: #ff0000;\"><a style=\"color: #ff0000;\" href=\"#topch7\"><em><strong>(Back to the Top)<\/strong><\/em><\/a><\/span><\/span><\/h5>\n<hr \/>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"learning_objectives editable block\" id=\"gob-ch12_s02_n01\">\n<h4 class=\"title\" id=\"halogenation\"><span style=\"color: #000000;\"><strong>Halogenation Reactions (Substitution Type)<\/strong><\/span><\/h4>\n<p><span style=\"color: #000000;\">In the presence of heat or light, alkanes can react with halogens to form <strong><em>alkyl halides (or haloalkanes). <\/em><\/strong>This type of reaction is called a <strong><em>substitution reaction<\/em><\/strong>, because the halogen atom is taking the place of (or substituting for)\u00a0one of the hydrogen atoms on the alkane structure. It should be noted that not all of the halogens react in the same way with alkanes.\u00a0<\/span><\/p>\n<ul>\n<li><span style=\"color: #000000;\"><strong>The reaction between alkanes and fluorine:\u00a0<\/strong><span style=\"font-family: Helvetica,Arial;\">This reaction is explosive even in the cold and dark, and you tend to get carbon and hydrogen fluoride produced, rather than the desired substitution reaction. It is of no particular interest to organic chemists, as the reaction can be very dangerous, and it does not yield the desired product. For example, the desired product would be the alkyl fluoride:<\/span><\/span><\/li>\n<\/ul>\n<div class=\"MathJax_Display\" style=\"text-align: center;\"><\/div>\n<div class=\"MathJax_Display\" style=\"text-align: center;\"><span style=\"color: #000000;\"><strong><span class=\"MathJax\" id=\"MathJax-Element-1-Frame\" role=\"presentation\"><span class=\"math\" id=\"MathJax-Span-1\"><span class=\"mrow\" id=\"MathJax-Span-2\"><span class=\"mi\" id=\"MathJax-Span-3\">C<\/span><span class=\"msubsup\" id=\"MathJax-Span-4\"><span class=\"mi\" id=\"MathJax-Span-5\">H<\/span><sub><span class=\"mn\" id=\"MathJax-Span-6\">4\u00a0\u00a0 <\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-7\">+\u00a0\u00a0 <\/span><span class=\"msubsup\" id=\"MathJax-Span-9\"><span class=\"mi\" id=\"MathJax-Span-10\">F<\/span><sub><span class=\"mn\" id=\"MathJax-Span-11\">2\u00a0\u00a0 <\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-12\">\u2192\u00a0\u00a0 <\/span><span class=\"mi\" id=\"MathJax-Span-13\"><span style=\"color: #ff0000;\">CH<sub>3<\/sub>F<\/span>\u00a0\u00a0 <\/span><span class=\"mo\" id=\"MathJax-Span-14\">+\u00a0\u00a0 <\/span><span class=\"mi\" id=\"MathJax-Span-16\">H<\/span><span class=\"mi\" id=\"MathJax-Span-17\">F<\/span><\/span><\/span><\/span><\/strong><\/span><\/div>\n<\/div>\n<\/div>\n<div class=\"MathJax_Display\" style=\"text-align: center;\"><\/div>\n<p class=\"MathJax_Display\" style=\"text-align: center;\"><span style=\"color: #000000;\">But the reaction goes so fast, that this is the result:<\/span><\/p>\n<div class=\"section\" id=\"gob-ch12_s02\" lang=\"en\">\n<div class=\"learning_objectives editable block\" id=\"gob-ch12_s02_n01\">\n<div class=\"MathJax_Display\" style=\"text-align: center;\"><\/div>\n<div class=\"MathJax_Display\" style=\"text-align: center;\"><span style=\"color: #000000;\"><strong><span class=\"MathJax\" id=\"MathJax-Element-1-Frame\" role=\"presentation\"><span class=\"math\" id=\"MathJax-Span-1\"><span class=\"mrow\" id=\"MathJax-Span-2\"><span class=\"mi\" id=\"MathJax-Span-3\">C<\/span><span class=\"msubsup\" id=\"MathJax-Span-4\"><span class=\"mi\" id=\"MathJax-Span-5\">H<\/span><sub><span class=\"mn\" id=\"MathJax-Span-6\">4\u00a0\u00a0 <\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-7\">+\u00a0\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-8\">2<\/span><span class=\"msubsup\" id=\"MathJax-Span-9\"><span class=\"mi\" id=\"MathJax-Span-10\">F<\/span><sub><span class=\"mn\" id=\"MathJax-Span-11\">2\u00a0\u00a0 <\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-12\">\u2192\u00a0\u00a0 <\/span><span class=\"mi\" id=\"MathJax-Span-13\"><span style=\"color: #ff0000;\">C\u00a0<\/span>\u00a0 <\/span><span class=\"mo\" id=\"MathJax-Span-14\">+\u00a0\u00a0 <\/span><span class=\"mn\" id=\"MathJax-Span-15\">4<\/span><span class=\"mi\" id=\"MathJax-Span-16\">H<\/span><span class=\"mi\" id=\"MathJax-Span-17\">F<\/span><\/span><\/span><\/span><\/strong><\/span><\/div>\n<div class=\"MathJax_Display\" style=\"text-align: center;\"><\/div>\n<ul>\n<li><span style=\"color: #000000;\"><strong>The reaction between alkanes and iodine: <\/strong><span style=\"font-family: Helvetica,Arial;\">Iodine does not react with the alkanes to any extent &#8211; at least, under normal lab conditions. So this reaction is not useful either.<\/span><\/span><\/li>\n<li><span style=\"color: #000000;\"><strong>The reactions between alkanes and chlorine or bromine: <\/strong><span style=\"font-family: Helvetica,Arial;\">There is no reaction in the dark, but if light and heat are present, the reaction will produce the desired alkyl halides. Thus, we will focus our discussion on halogenation reactions with chlorine and bromine.<\/span><\/span><\/li>\n<\/ul>\n<div class=\"mt-section\" id=\"section_2\">\n<h5 class=\"editable\"><em><strong><span style=\"color: #ff0000;\">The Reaction of Methane and Chlorine<\/span><\/strong><\/em><\/h5>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">In the presence of a flame, the reactions are rather like the fluorine one &#8211; producing a mixture of carbon and the hydrogen halide. The violence of the reaction drops considerably as you go from fluorine to chlorine to bromine. The interesting reactions happen in the presence of ultra-violet light (sunlight will do). These are photochemical reactions that happen at room temperature. We&#8217;ll look at the reactions with chlorine, although the reactions with bromine are similar, but evolve more slowly.<\/span><\/span><\/p>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">In the substitution reaction, a\u00a0hydrogen atom in the methane\u00a0is replaced by a chlorine atom. This can happen multiple times, until all the hydrogens are replaced. Ultimately,\u00a0the longer the reaction proceeds, the more hydrogens in the alkane are replaced.\u00a0 Thus, you end up with a mixture of chloromethane (CH<sub>3<\/sub>Cl), dichloromethane (CH<sub>2<\/sub>Cl<sub>2<\/sub>), trichloromethane (CHCl<sub>3<\/sub>)\u00a0and tetrachloromethane (CCl<sub>4<\/sub>).<\/span><\/span><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/halogenation-of-methane.png\"><img loading=\"lazy\" decoding=\"async\" width=\"502\" height=\"239\" class=\"alignnone wp-image-2579\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/halogenation-of-methane.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/halogenation-of-methane.png 693w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/halogenation-of-methane-300x143.png 300w\" sizes=\"(max-width: 502px) 100vw, 502px\" \/><\/a><\/p>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">The original mixture of a colorless gas (CH<sub>4<\/sub>)\u00a0and a green gas (Cl<sub>2<\/sub>)\u00a0would produce steamy fumes of hydrogen chloride (HCl)\u00a0and a mist of organic liquids (mixture of the chlorinated methane). All of the organic products are liquid at room temperature with the exception of the chloromethane (CH<sub>3<\/sub>Cl)\u00a0which is a gas.<\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">This substitution reaction is an example of a radical reaction, where only one electron is transferred at a time.\u00a0 The heat\u00a0or light, initiates the reaction by breaking the bond between the two Cl atoms in the chloride ion.\u00a0 This forms two <strong><em>radicals<\/em><\/strong>. A <em><strong>radical<\/strong><\/em>\u00a0is an atom, molecule, or ion that has unpaired valence electrons. Thus, they are very unstable and reactive. In the diagram below, the first step of the halogenation reaction is shown below.\u00a0 This is termed <strong><em>initiation<\/em><\/strong>.<\/span><\/p>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">\u00a0<a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/chloride-radicals.png\"><img loading=\"lazy\" decoding=\"async\" width=\"509\" height=\"182\" class=\"alignnone wp-image-2582\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/chloride-radicals.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/chloride-radicals.png 757w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/chloride-radicals-300x107.png 300w\" sizes=\"(max-width: 509px) 100vw, 509px\" \/><\/a><\/span><\/span><\/p>\n<h4 style=\"text-align: left;\"><strong><span style=\"color: #000000;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0Initiation Reaction<\/span><\/strong><\/h4>\n<p><span style=\"color: #000000;\">Once the radical is initiated, it will attack the alkane, in this case methane (CH<sub>4<\/sub>), and create a new carbon radical.\u00a0 This stage of the reaction is termed <strong><em>propagation<\/em><\/strong>, as one radical species creates, or propagates, another radical.<\/span><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/propagation-reaction-methane.png\"><img loading=\"lazy\" decoding=\"async\" width=\"568\" height=\"170\" class=\"alignnone wp-image-2584\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/propagation-reaction-methane.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/propagation-reaction-methane.png 934w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/propagation-reaction-methane-300x90.png 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/propagation-reaction-methane-768x229.png 768w\" sizes=\"(max-width: 568px) 100vw, 568px\" \/><\/a><\/p>\n<h4><span style=\"color: #000000;\"><strong>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Propagation Reaction<\/strong><\/span><\/h4>\n<p><span style=\"color: #000000;\">The final stage of a radical reaction is the <strong><em>termination reaction<\/em><\/strong> which quenches the radical species present.\u00a0 For the methane &#8211; chlorine reaction this is the formation of the chloromethane (CH<sub>3<\/sub>Cl).<\/span><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/termination-reation.png\"><img loading=\"lazy\" decoding=\"async\" width=\"540\" height=\"173\" class=\"alignnone wp-image-2586\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/termination-reation.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/termination-reation.png 874w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/termination-reation-300x96.png 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/termination-reation-768x246.png 768w\" sizes=\"(max-width: 540px) 100vw, 540px\" \/><\/a><\/p>\n<h4><span style=\"color: #000000;\"><strong>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/strong><strong>Termination Reaction<\/strong><\/span><\/h4>\n<p><span style=\"color: #000000;\">In summary, radical reactions occur in three stages:<\/span><\/p>\n<ul>\n<li><span style=\"color: #000000;\"><strong>Initiation &#8211;<\/strong> where a radical species is generated, generally by heat, light, or other catalytic process.<\/span><\/li>\n<li><span style=\"color: #000000;\"><strong>Propagation &#8211;<\/strong> where one radical species interacts with another molecule to create another radical species.<\/span><\/li>\n<li><span style=\"color: #000000;\"><strong>Termination &#8211;<\/strong> where two radical species interact and quench the radical reaction an form a stable product.<\/span><\/li>\n<\/ul>\n<\/div>\n<div class=\"mt-section\" id=\"section_3\">\n<h5 class=\"editable\" style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<h5 class=\"editable\"><span style=\"color: #ff0000;\"><em><strong>Larger Alkanes and Chlorine<\/strong><\/em><\/span><\/h5>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">As seen with the methane example, if you halogenate larger alkanes, you would again get a mixture of substitution products, but it is worth just looking briefly at what happens if only one of the hydrogen atoms gets substituted (monosubstitution) &#8211; just to show that things aren&#8217;t always as straightforward as they seem! For example, with propane, you could get one of two isomers:<\/span><\/span><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/halogenation-ii.png\"><img loading=\"lazy\" decoding=\"async\" width=\"536\" height=\"420\" class=\"alignnone wp-image-2592\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/halogenation-ii.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/halogenation-ii.png 720w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/halogenation-ii-300x235.png 300w\" sizes=\"(max-width: 536px) 100vw, 536px\" \/><\/a><\/p>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\"><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">If chance was the only factor, you would expect to get three times as much of the isomer with the chlorine on the end. There are 6 hydrogens that could get replaced on the end carbon atoms compared with only 2 in the middle. In fact, you get about the same amount of each of the two isomers. If you use bromine instead of chlorine, the great majority of the product is where the bromine is attached to the center carbon atom.\u00a0 Why does this happen?<\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">It has to do with the stability of the carbon radical intermediate that forms during the reaction.\u00a0 Carbons that have more carbon neighbors will more easily lose a hydrogen and form a carbon radical intermediate.\u00a0 The neighboring carbons, being larger than the neighboring hydrogen atoms, can help stabilize the formation of the carbon radical. Thus, in the\u00a0halogenation reaction tertiary carbons will be the most reactive positions, followed by secondary carbons and finally primary carbons.\u00a0 Quaternary carbons are unreactive as they do not have any hydrogens available that can be substituted by a halogen.<\/span><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/carbon-radicals.png\"><img loading=\"lazy\" decoding=\"async\" width=\"561\" height=\"266\" class=\"alignnone wp-image-2595\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/carbon-radicals.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/carbon-radicals.png 970w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/carbon-radicals-300x142.png 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/carbon-radicals-768x364.png 768w\" sizes=\"(max-width: 561px) 100vw, 561px\" \/><\/a><\/p>\n<\/div>\n<div class=\"mt-section\" id=\"section_4\">\n<hr \/>\n<h5 class=\"editable\"><span style=\"color: #ff0000;\"><strong><em>Halogenation Reactions with Cycloalkanes<\/em><\/strong><\/span><\/h5>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">The reactions of the cycloalkanes are generally just the same as the alkanes, with hydrogen atoms on the cyclic ring structure being replaced by the halogen atom. For example i<span style=\"font-family: Helvetica;\">n the presence of UV light, cyclopropane will undergo substitution reactions with chlorine or bromine just like a non-cyclic alkane. <\/span><\/span><\/span><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/cyclopropane-halogenation-i.png\"><img loading=\"lazy\" decoding=\"async\" width=\"539\" height=\"123\" class=\"alignnone wp-image-2598\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/cyclopropane-halogenation-i.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/cyclopropane-halogenation-i.png 717w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/cyclopropane-halogenation-i-300x68.png 300w\" sizes=\"(max-width: 539px) 100vw, 539px\" \/><\/a><\/p>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">However,\u00a0the\u00a0small ring structures\u00a0&#8211; particularly cyclopropane &#8211; also have the ability to react in the dark. In the absence of UV light, cyclopropane can undergo addition reactions in which the ring is broken. For example, with bromine, cyclopropane gives following linear compound.<\/span><\/span><\/p>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/cyclopropane-halogenation.png\"><img loading=\"lazy\" decoding=\"async\" width=\"547\" height=\"115\" class=\"alignnone wp-image-2597\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/cyclopropane-halogenation.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/cyclopropane-halogenation.png 745w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/cyclopropane-halogenation-300x63.png 300w\" sizes=\"(max-width: 547px) 100vw, 547px\" \/><\/a><\/p>\n<p><span><span style=\"color: #000000; font-family: Helvetica,Arial;\">This can still happen in the presence of UV light &#8211; but you will get a mixture of the substitution reactions as well. The ring is broken because cyclopropane suffers badly from ring strain. Recall that the bond angles in the ring are 60\u00b0 rather than the normal value of about 109.5\u00b0 when the carbon makes four single bonds. <\/span><\/span><\/p>\n<div class=\"qandaset block\" id=\"gob-ch12_s07_qs01\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><strong><em>Concept Review Exercises<\/em><\/strong><\/span><\/h5>\n<ol class=\"qandadiv\" id=\"gob-ch12_s07_qs01_qd01\">\n<li class=\"qandaentry\" id=\"gob-ch12_s07_qs01_qd01_qa01\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s07_qs01_p01\"><span style=\"color: #000000;\">Why are alkanes sometimes called paraffins?<\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s07_qs01_qd01_qa02\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s07_qs01_p03\"><span style=\"color: #000000;\">Which halogen reacts most readily with alkanes? Which reacts least readily?<\/span><\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div class=\"qandaset block\" id=\"gob-ch12_s07_qs01_ans\">\n<h5 class=\"title\"><strong><em><span style=\"color: #ff0000;\">Answers<\/span><\/em><\/strong><\/h5>\n<ol class=\"qandadiv\">\n<li class=\"qandaentry\" id=\"gob-ch12_s07_qs01_qd01_qa01_ans\">\n<div class=\"answer\">\n<p class=\"para\" id=\"gob-ch12_s07_qs01_p02_ans\"><span style=\"color: #000000;\">Alkanes do not react with many common chemicals. They are sometimes called paraffins, from the Latin <em class=\"emphasis\">parum affinis<\/em>, meaning \u201clittle affinity.\u201d<\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s07_qs01_qd01_qa02_ans\">\n<div class=\"answer\">\n<p class=\"para\" id=\"gob-ch12_s07_qs01_p04_ans\"><span style=\"color: #000000;\">most readily: F<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>; least readily: I<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub><\/span><\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<p><span style=\"color: #000000;\">A wide variety of interesting and often useful compounds have one or more halogen atoms per molecule. For example, methane (CH<sub class=\"subscript\"><span style=\"font-size: small;\">4<\/span><\/sub>) can react with chlorine (Cl<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>), replacing one, two, three, or all four hydrogen atoms with Cl atoms. Several halogenated products derived from methane and ethane (CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>CH<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>) are listed in Table 7.6\u00a0along with some of their uses.<\/span><\/p>\n<h4><span style=\"color: #000000;\"><strong>Table 7.6: Some Halogenated Hydrocarbons<\/strong><\/span><\/h4>\n<p><a href=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/halogenated_alkanes.png\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"1009\" class=\"alignnone size-large wp-image-2612\" alt=\"\" src=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/halogenated_alkanes-1024x1009.png\" srcset=\"https:\/\/wou.edu\/chemistry\/files\/2017\/01\/halogenated_alkanes-1024x1009.png 1024w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/halogenated_alkanes-300x296.png 300w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/halogenated_alkanes-768x756.png 768w, https:\/\/wou.edu\/chemistry\/files\/2017\/01\/halogenated_alkanes.png 1068w\" sizes=\"(max-width: 1024px) 100vw, 1024px\" \/><\/a><\/p>\n<div class=\"callout editable block\" id=\"gob-ch12_s08_n06\">\n<hr \/>\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><strong><em>To Your Health: Halogenated Hydrocarbons<\/em><\/strong><\/span><\/h5>\n<p class=\"para\" id=\"gob-ch12_s08_p13\"><span style=\"color: #000000;\">Once widely used in consumer products, many chlorinated hydrocarbons are suspected carcinogens (cancer-causing substances) and also are known to cause severe liver damage. An example is carbon tetrachloride (CCl<sub class=\"subscript\"><span style=\"font-size: small;\">4<\/span><\/sub>), once used as a dry-cleaning solvent and in fire extinguishers but no longer recommended for either use. Even in small amounts, its vapor can cause serious illness if exposure is prolonged. Moreover, it reacts with water at high temperatures to form deadly phosgene (COCl<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>) gas, which makes the use of CCl<sub class=\"subscript\"><span style=\"font-size: small;\">4<\/span><\/sub> in fire extinguishers particularly dangerous.<\/span><\/p>\n<p class=\"para\" id=\"gob-ch12_s08_p14\"><span style=\"color: #000000;\">Ethyl chloride, in contrast, is used as an external local anesthetic. When sprayed on the skin, it evaporates quickly, cooling the area enough to make it insensitive to pain. It can also be used as an emergency general anesthetic.<\/span><\/p>\n<p class=\"para\" id=\"gob-ch12_s08_p15\"><span style=\"color: #000000;\">Bromine-containing compounds are widely used in fire extinguishers and as fire retardants on clothing and other materials. Because they too are toxic and have adverse effects on the environment, scientists are engaged in designing safer substitutes for them, as for many other halogenated compounds.<\/span><\/p>\n<hr \/>\n<\/div>\n<div class=\"callout block\" id=\"gob-ch12_s08_n07\">\n<h5 class=\"title\"><span style=\"color: #ff0000;\"><strong><em>To Your Health: Chlorofluorocarbons and the Ozone Layer<\/em><\/strong><\/span><\/h5>\n<p class=\"para\" id=\"gob-ch12_s08_p16\"><span style=\"color: #000000;\">Alkanes substituted with both fluorine (F) and chlorine (Cl) atoms have been used as the dispersing gases in aerosol cans, as foaming agents for plastics, and as refrigerants. Two of the best known of these chlorofluorocarbons (CFCs) are listed in Table 7.6.<\/span><\/p>\n<p class=\"para\" id=\"gob-ch12_s08_p17\"><span style=\"color: #000000;\">Chlorofluorocarbons contribute to the greenhouse effect in the lower atmosphere. They also diffuse into the stratosphere, where they are broken down by ultraviolet (UV) radiation to release Cl atoms. These in turn break down the ozone (O<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>) molecules that protect Earth from harmful UV radiation. Worldwide action has reduced the use of CFCs and related compounds. The CFCs and other Cl- or bromine (Br)-containing ozone-destroying compounds are being replaced with more benign substances. Hydrofluorocarbons (HFCs), such as CH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>FCF<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>, which have no Cl or Br to form radicals, are one alternative. Another is hydrochlorofluorocarbons (HCFCs), such as CHCl<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>CF<sub class=\"subscript\"><span style=\"font-size: small;\">3<\/span><\/sub>. HCFC molecules break down more readily in the troposphere, and fewer ozone-destroying molecules reach the stratosphere.<\/span><\/p>\n<div class=\"informalfigure medium\">\n<p><img loading=\"lazy\" decoding=\"async\" width=\"448\" height=\"499\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/3d69a9fb89c780a529b250f3ff8f50fb.jpg\" \/><\/p>\n<p class=\"para\"><strong><span style=\"color: #000000;\">Figure 7.13. Ozone Depletion in the Upper Atmosphere.<\/span><\/strong> <span style=\"color: #000000;\">Ozone in the upper atmosphere shields Earth\u2019s surface from UV radiation from the sun, which can cause skin cancer in humans and is also harmful to other animals and to some plants. Ozone \u201choles\u201d in the upper atmosphere (the gray, pink, and purple areas at the center) are large areas of substantial ozone depletion. They occur mainly over Antarctica from late August through early October and fill in about mid-November. Ozone depletion has also been noted over the Arctic regions. The largest ozone hole ever observed occurred on 24 September 2006.<\/span><\/p>\n<div class=\"copyright\">\n<p class=\"para\"><span style=\"color: #000000;\">Source: Image courtesy of <a href=\"http:\/\/ozonewatch.gsfc.nasa.gov\/daily.php?date=2006-09-24\">NASA<\/a>.<\/span><\/p>\n<h5 class=\"para\" style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<\/div>\n<\/div>\n<\/div>\n<hr \/>\n<h4 id=\"cracking\"><strong><span style=\"color: #000000;\">Cracking Alkanes<\/span><\/strong><\/h4>\n<p><span style=\"color: #000000;\">What is cracking? Cracking is the name given to breaking up large hydrocarbon molecules into smaller and more useful bits. This is achieved by using high pressures and temperatures without a <strong><em>catalyst<\/em><\/strong>, or lower temperatures and pressures in the presence of a <strong><em>catalyst<\/em><\/strong>.\u00a0A <em><strong>catalyst<\/strong><\/em> is <span>a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change.<\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">The source of the large hydrocarbon molecules is often the naphtha fraction or the gas oil fraction from the fractional distillation of crude oil (petroleum). These fractions are obtained from the distillation process as liquids, but are re-vaporized into the gaseous phase before cracking. There isn&#8217;t any single unique reaction happening in the cracker. The hydrocarbon molecules are broken up in a fairly random way to produce mixtures of smaller hydrocarbons, some of which have carbon-carbon double bonds. One possible reaction involving the hydrocarbon <span class=\"MathJax\" id=\"MathJax-Element-1-Frame\" role=\"presentation\"><span class=\"math\" id=\"MathJax-Span-1\"><span class=\"mrow\" id=\"MathJax-Span-2\"><span class=\"msubsup\" id=\"MathJax-Span-3\"><span class=\"mi\" id=\"MathJax-Span-4\">C<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-5\"><span class=\"mrow\" id=\"MathJax-Span-6\"><span class=\"mn\" id=\"MathJax-Span-7\"><span style=\"font-size: small;\">15<\/span><\/span><\/span><\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-8\"><span class=\"mi\" id=\"MathJax-Span-9\">H<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-10\"><span class=\"mrow\" id=\"MathJax-Span-11\"><span class=\"mn\" id=\"MathJax-Span-12\"><span style=\"font-size: small;\">32<\/span><\/span><\/span><\/span><\/sub><\/span><\/span><\/span><\/span> might be:<\/span><\/p>\n<div class=\"MathJax_Display\"><span class=\"MathJax\" id=\"MathJax-Element-2-Frame\" role=\"presentation\"><span class=\"math\" id=\"MathJax-Span-13\"><span><span class=\"mrow\" id=\"MathJax-Span-14\"><span class=\"msubsup\" id=\"MathJax-Span-15\"><span class=\"mi\" id=\"MathJax-Span-16\">C<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-17\"><span class=\"mrow\" id=\"MathJax-Span-18\"><span class=\"mn\" id=\"MathJax-Span-19\">15<\/span><\/span><\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-20\"><span class=\"mi\" id=\"MathJax-Span-21\">H<\/span><sub><span class=\"texatom\" id=\"MathJax-Span-22\"><span class=\"mrow\" id=\"MathJax-Span-23\"><span class=\"mn\" id=\"MathJax-Span-24\">32\u00a0 <\/span><\/span><\/span><\/sub><\/span><span class=\"mo\" id=\"MathJax-Span-25\">\u2192\u00a0 <\/span><span class=\"munder\" id=\"MathJax-Span-26\"><span class=\"mrow\" id=\"MathJax-Span-27\"><span class=\"mn\" id=\"MathJax-Span-28\">2<\/span><span class=\"msubsup\" id=\"MathJax-Span-29\"><span class=\"mi\" id=\"MathJax-Span-30\">C<\/span><sub><span class=\"mn\" id=\"MathJax-Span-31\">2<\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-32\"><span class=\"mi\" id=\"MathJax-Span-33\">H<\/span><sub><span class=\"mn\" id=\"MathJax-Span-34\">4\u00a0 <\/span><\/sub><\/span><\/span><\/span><span class=\"mo\" id=\"MathJax-Span-36\">+\u00a0 <\/span><span class=\"munder\" id=\"MathJax-Span-37\"><span class=\"mrow\" id=\"MathJax-Span-38\"><span class=\"msubsup\" id=\"MathJax-Span-39\"><span class=\"mi\" id=\"MathJax-Span-40\">C<\/span><sub><span class=\"mn\" id=\"MathJax-Span-41\">3<\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-42\"><span class=\"mi\" id=\"MathJax-Span-43\">H<\/span><sub><span class=\"mn\" id=\"MathJax-Span-44\">6<\/span><\/sub><\/span><\/span><span class=\"mtext\" id=\"MathJax-Span-45\"> <\/span><\/span><span class=\"mo\" id=\"MathJax-Span-46\">+\u00a0 <\/span><span class=\"munder\" id=\"MathJax-Span-47\"><span class=\"mrow\" id=\"MathJax-Span-48\"><span class=\"msubsup\" id=\"MathJax-Span-49\"><span class=\"mi\" id=\"MathJax-Span-50\">C<\/span><sub><span class=\"mn\" id=\"MathJax-Span-51\">8<\/span><\/sub><\/span><span class=\"msubsup\" id=\"MathJax-Span-52\"><span class=\"mi\" id=\"MathJax-Span-53\">H<\/span><span class=\"texatom\" id=\"MathJax-Span-54\"><span class=\"mrow\" id=\"MathJax-Span-55\"><span class=\"mn\" id=\"MathJax-Span-56\"><sub>18<\/sub>\u00a0 <\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/div>\n<p><span style=\"color: #000000;\">Or, showing more clearly what happens to the various atoms and bonds:<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" width=\"383\" height=\"226\" class=\"internal\" alt=\"\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/16994\/crackmodel.gif?revision=1&amp;size=bestfit&amp;width=383&amp;height=226\" \/><\/p>\n<p><span style=\"color: #000000;\">This is only one way in which this particular molecule might break up. Notice that in addition to producing smaller alkanes, the cracking reaction can also produce alkenes with double bonds. In this case, the alkenes &#8211;\u00a0ethene (C<sub>2<\/sub>H<sub>4<\/sub>) and propene (C<sub>3<\/sub>H<sub>6<\/sub>) &#8211;\u00a0are important materials for making plastics or producing other organic chemicals. The octane is one of the molecules found in petrol (gasoline).<\/span><\/p>\n<hr \/>\n<div class=\"mt-section\" id=\"section_2\">\n<h5><span style=\"color: #ff0000;\"><em><strong>Looking Closer: An Alkane Basis for Properties of Other Compounds<\/strong><\/em><\/span><\/h5>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"section\" id=\"gob-ch12_s06\" lang=\"en\">\n<div class=\"callout block\" id=\"gob-ch12_s06_n03\">\n<p class=\"para\" id=\"gob-ch12_s06_p05\"><span style=\"color: #000000;\">An understanding of the physical properties of the alkanes is important in that petroleum and natural gas and the many products derived from them\u2014gasoline, bottled gas, solvents, plastics, and more\u2014are composed primarily of alkanes. This understanding is also vital because it is the basis for describing the properties of other organic and biological compound families. For example, large portions of the structures of lipids consist of nonpolar alkyl groups. Lipids include the dietary fats and fatlike compounds called phospholipids and sphingolipids that serve as structural components of living tissues. These compounds have both polar and nonpolar groups, enabling them to bridge the gap between water-soluble and water-insoluble phases. This characteristic is essential for the selective permeability of cell membranes.<\/span><\/p>\n<div class=\"informalfigure large\">\n<p><img loading=\"lazy\" decoding=\"async\" width=\"524\" height=\"339\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/916145918b4900ad6ddfc77069f8bcee.jpg\" \/><\/p>\n<p class=\"para\"><span style=\"color: #000000;\"><strong>Figure 7.13 Comparision of Lipids and Alkanes.<\/strong> Tripalmitin (a), a typical fat molecule, has long hydrocarbon chains typical of most lipids. Compare these chains to hexadecane (b), an alkane with 16 carbon atoms.<\/span><\/p>\n<h5 class=\"para\" style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<hr \/>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"section\" id=\"gob-ch12_s07\" lang=\"en\">\n<div class=\"key_takeaways editable block\" id=\"gob-ch12_s07_n03\">\n<ul class=\"itemizedlist\" id=\"gob-ch12_s07_l03\"><\/ul>\n<\/div>\n<\/div>\n<div class=\"section end-of-chapter\" id=\"gob-ch12_s10\" lang=\"en\">\n<div class=\"callout editable block\" id=\"gob-ch12_s10_n01\">\n<h3><strong>7.5 Chapter Summary<\/strong><\/h3>\n<p class=\"para\" id=\"gob-ch12_s10_p01\"><span style=\"color: #000000;\"><em class=\"emphasis\">To ensure that you understand the material in this chapter, you should review the meanings of the following bold terms in the summary and ask yourself how they relate to the topics in the chapter.<\/em><\/span><\/p>\n<p class=\"para\" id=\"gob-ch12_s10_p02\"><span style=\"color: #000000;\"><strong class=\"emphasis bold\">Organic chemistry<\/strong> is the chemistry of carbon compounds, and <strong class=\"emphasis bold\">inorganic chemistry<\/strong> is the chemistry of all the other elements. Carbon atoms can form stable covalent bonds with other carbon atoms and with atoms of other elements, and this property allows the formation the tens of millions of organic compounds. <strong class=\"emphasis bold\">Hydrocarbons<\/strong> contain only hydrogen and carbon atoms.<\/span><\/p>\n<p class=\"para\" id=\"gob-ch12_s10_p03\"><span style=\"color: #000000;\">Hydrocarbons in which each carbon atom is bonded to four other atoms are called <strong class=\"emphasis bold\">alkanes<\/strong> or <strong class=\"emphasis bold\">saturated hydrocarbons<\/strong>. They have the general formula C<sub class=\"subscript\"><em class=\"emphasis\"><span style=\"font-size: small;\">n<\/span><\/em><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub><sub class=\"subscript\"><em class=\"emphasis\"><span style=\"font-size: small;\">n<\/span><\/em><\/sub> <sub class=\"subscript\"><span style=\"font-size: small;\">+ 2<\/span><\/sub>. Any given alkane differs from the next one in a series by a CH<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub> unit. Any family of compounds in which adjacent members differ from each other by a definite factor is called a <strong class=\"emphasis bold\">homologous series<\/strong>.<\/span><\/p>\n<p class=\"para\" id=\"gob-ch12_s10_p04\"><span style=\"color: #000000;\">Carbon atoms in alkanes can form straight chains or branched chains. Two or more compounds having the same molecular formula but different structural formulas are <strong class=\"emphasis bold\">isomers<\/strong> of each other. There are no isomeric forms for the three smallest alkanes; beginning with C<sub class=\"subscript\"><span style=\"font-size: small;\">4<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">10<\/span><\/sub>, all other alkanes have isomeric forms.<\/span><\/p>\n<p class=\"para\"><span style=\"color: #000000;\">Cycloalkanes are hydrocarbons whose molecules are closed rings rather than straight or branched chains. A <strong class=\"emphasis bold\">cyclic hydrocarbon<\/strong> is a hydrocarbon with a ring of carbon atoms.<\/span><\/p>\n<p class=\"para\" id=\"gob-ch12_s10_p05\"><span style=\"color: #000000;\">Recall that\u00a0a <strong class=\"emphasis bold\">structural formula<\/strong> shows all the carbon and hydrogen atoms and how they are attached to one another. A <strong class=\"emphasis bold\">condensed structural formula<\/strong> shows the hydrogen atoms right next to the carbon atoms to which they are attached. A <strong class=\"emphasis bold\">line-angle formula<\/strong> is a formula in which carbon atoms are implied at the corners and ends of lines. Each carbon atom is understood to be attached to enough hydrogen atoms to give each carbon atom four bonds<\/span><\/p>\n<p class=\"para\" id=\"gob-ch12_s10_p07\"><span style=\"color: #000000;\">The physical properties of alkanes reflect the fact that alkane molecules are nonpolar. Alkanes are insoluble in water and less dense than water.<\/span><\/p>\n<p class=\"para\" id=\"gob-ch12_s10_p08\"><span style=\"color: #000000;\">Alkanes are generally unreactive toward laboratory acids, bases, oxidizing agents, and reducing agents. They do burn (undergo <strong class=\"emphasis bold\">combustion reactions<\/strong>).<\/span><\/p>\n<p class=\"para\" id=\"gob-ch12_s10_p09\"><span style=\"color: #000000;\">Alkanes react with halogens by substituting one or more halogen atoms for hydrogen atoms to form halogenated hydrocarbons. This reaction is called <strong><em>halogenation<\/em><\/strong>. An <em><strong class=\"emphasis bold\">alkyl halide (haloalkane)<\/strong><\/em> is a compound resulting from the replacement of a hydrogen atom of an alkane with a halogen atom.<\/span><\/p>\n<p class=\"para\"><span style=\"color: #000000;\">Larger alkanes can be broken into smaller alkanes and alkenes\u00a0using high heat or catalysts. These reactions are called <strong><em>cracking reactions<\/em><\/strong>.<\/span><\/p>\n<h5 class=\"para\" style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<hr \/>\n<\/div>\n<div class=\"qandaset block\" id=\"gob-ch12_s10_qs01\">\n<h3 class=\"title\" id=\"exercisesend\"><strong>7.6\u00a0End-of-Chapter\u00a0Exercises<\/strong><\/h3>\n<ol class=\"qandadiv\" id=\"gob-ch12_s10_qs01_qd01\">\n<li class=\"qandaentry\" id=\"gob-ch12_s10_qs01_qd01_qa01\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s10_qs01_p01\"><span style=\"color: #000000;\">You find an unlabeled jar containing a solid that melts at 48\u00b0C. It ignites readily and burns readily. The substance is insoluble in water and floats on the surface. Is the substance likely to be organic or inorganic?<\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s10_qs01_qd01_qa02\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s10_qs01_p03\"><span style=\"color: #000000;\">What is the danger in swallowing a liquid alkane?<\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s10_qs01_qd01_qa03\"><span style=\"color: #000000;\">Distinguish between lighter and heavier liquid alkanes in terms of their effects on the skin.<\/span>\n<div class=\"question\">\n<ol class=\"orderedlist\" id=\"gob-ch12_s10_qs01_l01\"><\/ol>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s10_qs01_qd01_qa06\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s10_qs01_p10\"><span style=\"color: #000000;\">Following is the line formula for an alkane. Draw the condensed structure.<\/span><\/p>\n<div class=\"informalfigure large\"><img loading=\"lazy\" decoding=\"async\" width=\"457\" height=\"75\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/5d89195af85ea57dfb9e2a9134442518.jpg\" \/><\/div>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s10_qs01_qd01_qa07\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s10_qs01_p12\"><span style=\"color: #000000;\">Write equations for the complete combustion of each compound.<\/span><\/p>\n<ol class=\"orderedlist\" id=\"gob-ch12_s10_qs01_l03\">\n<li><span style=\"color: #000000;\">butane, C<sub>4<\/sub>H<sub>10<\/sub>\u00a0(a common lighter fluid)<\/span><\/li>\n<li><span style=\"color: #000000;\">octane, C<sub>8<\/sub>H<sub>18 <\/sub>(a typical hydrocarbon in gasoline).<\/span><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s10_qs01_qd01_qa08\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s10_qs01_p13\"><span style=\"color: #000000;\">The density of a gasoline sample is 0.690 g\/mL. On the basis of the complete combustion of octane, calculate the amount in grams of carbon dioxide (CO<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>) and water (H<sub class=\"subscript\"><span style=\"font-size: small;\">2<\/span><\/sub>O) formed per gallon (3.78 L) of the gasoline when used in an automobile.<\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s10_qs01_qd01_qa09\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s10_qs01_p15\"><span style=\"color: #000000;\">Draw the structures for four of the nine\u00a0isomeric hexanes (C<sub><span style=\"font-size: small;\">7<\/span><\/sub>H<sub class=\"subscript\"><span style=\"font-size: small;\">16<\/span><\/sub>).<\/span><\/p>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s10_qs01_qd01_qa10\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s10_qs01_p17\"><span style=\"color: #000000;\">Indicate whether the structures in each set represent the same compound or isomers.<\/span><\/p>\n<ol class=\"orderedlist\" id=\"gob-ch12_s10_qs01_l05\">\n<li>\n<div class=\"informalfigure large\"><img loading=\"lazy\" decoding=\"async\" width=\"435\" height=\"63\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/e69091f6c4903a4dcebf8fca5b8c35a5.jpg\" \/><\/div>\n<\/li>\n<li>\n<div class=\"informalfigure large\"><img loading=\"lazy\" decoding=\"async\" width=\"446\" height=\"97\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/18aa2481919139a10ff5043b79dfbb25.jpg\" \/><\/div>\n<\/li>\n<li>\n<div class=\"informalfigure large\"><img loading=\"lazy\" decoding=\"async\" width=\"446\" height=\"63\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/2a82d4fb999e635a0b1bbdf54ac67acb.jpg\" \/><\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li class=\"qandaentry\" id=\"gob-ch12_s10_qs01_qd01_qa11\">\n<div class=\"question\">\n<p class=\"para\" id=\"gob-ch12_s10_qs01_p18\"><span style=\"color: #000000;\">Consider the line-angle formulas shown here and answer the questions.<\/span><\/p>\n<div class=\"informalfigure large\"><img loading=\"lazy\" decoding=\"async\" width=\"449\" height=\"159\" src=\"http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/section_15\/95bde77d2f87de419dbd0b80bbbf47d3.jpg\" \/><\/div>\n<ol class=\"orderedlist\" id=\"gob-ch12_s10_qs01_l07\">\n<li><span style=\"color: #000000;\">Which pair of formulas represents isomers? Draw each structure.<\/span><\/li>\n<li><span style=\"color: #000000;\">Which formula represents an alkyl halide?\u00a0 Write its condensed structural formula.<\/span><\/li>\n<li><span style=\"color: #000000;\">Which formula represents a cyclic alkane?<\/span><\/li>\n<li><span style=\"color: #000000;\">That is the molecular formula of the compound represented by (i)?<\/span><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<hr \/>\n<h5 style=\"text-align: right;\"><a href=\"#topch7\"><span style=\"color: #ff0000;\"><em><strong>(Back to the Top)<\/strong><\/em><\/span><\/a><\/h5>\n<h3 id=\"refs7\"><span style=\"color: #ff0000;\"><strong>7.7 References<\/strong><\/span><\/h3>\n<p><span style=\"color: #000000;\">Text for this chapter has been adapted from the creative commons resources listed below, unless otherwise noted in the text.<\/span><\/p>\n<ol>\n<li><span style=\"color: #000000;\">Organic Chemistry (2016) Libretexts, U.C. Davis, Licenced under:<\/span> <span style=\"color: #ff0000;\"><a style=\"color: #ff0000;\" href=\"http:\/\/creativecommons.org\/licenses\/by-nc-sa\/3.0\/us\/\" rel=\"license\">Creative Commons Attribution-Noncommercial-Share Alike 3.0 United States License<\/a>.<\/span> <span style=\"color: #000000;\">Available at:<\/span> <span style=\"color: #ff0000;\"><a style=\"color: #ff0000;\" href=\"https:\/\/chem.libretexts.org\/Core\/Organic_Chemistry\">https:\/\/chem.libretexts.org\/Core\/Organic_Chemistry <\/a><\/span><span style=\"color: #000000;\"><\/span><\/li>\n<li><span style=\"color: #000000;\">Inhalant. (2017, February 12). In <i>Wikipedia, The Free Encyclopedia<\/i>. Retrieved 01:21, February 13, 2017, from <span style=\"color: #ff0000;\"><a class=\"external free\" style=\"color: #ff0000;\" href=\"https:\/\/en.wikipedia.org\/w\/index.php?title=Inhalant&amp;oldid=765135147\">https:\/\/en.wikipedia.org\/w\/index.php?title=Inhalant&amp;oldid=765135147<\/a> <\/span><\/span><\/li>\n<li><span style=\"color: #000000;\">Anonymous. (2012) Introduction to Chemistry: General, Organic, and Biological (V1.0). Published under Creative Commons by-nc-sa 3.0. Available at:<\/span> <span style=\"color: #ff0000;\"><a style=\"color: #ff0000;\" href=\"https:\/\/archive.org\/details\/fwk-archive-20121229-2547\">http:\/\/2012books.lardbucket.org\/books\/introduction-to-chemistry-general-organic-and-biological\/index.html<\/a><\/span><span style=\"color: #000000;\"><\/span><\/li>\n<li><span style=\"color: #000000;\">Physical and Theoretical Chemistry (2017) Libretexts, U.C. Davis, Licenced under:<\/span> <span style=\"color: #ff0000;\"><a style=\"color: #ff0000;\" href=\"http:\/\/creativecommons.org\/licenses\/by-nc-sa\/3.0\/us\/\" rel=\"license\">Creative Commons Attribution-Noncommercial-Share Alike 3.0 United States License<\/a>.<\/span> <span style=\"color: #000000;\">Available at:<\/span> <span style=\"color: #ff0000;\"><a style=\"color: #ff0000;\" href=\"https:\/\/chem.libretexts.org\/Core\/Physical_and_Theoretical_Chemistry\/Chemical_Bonding\/General_Principles_of_Chemical_Bonding\/Bond_Energies\">https:\/\/chem.libretexts.org\/Core\/Physical_and_Theoretical_Chemistry\/Chemical_Bonding\/General_Principles_of_Chemical_Bonding\/Bond_Energies<\/a>.<\/span><\/li>\n<li><span style=\"color: #000000;\">Petroleum. (2017, February 14). In <i>Wikipedia, The Free Encyclopedia<\/i>. Retrieved 06:29, February 16, 2017, from<\/span> <span style=\"color: #ff0000;\"><a class=\"external free\" style=\"color: #ff0000;\" href=\"https:\/\/en.wikipedia.org\/w\/index.php?title=Petroleum&amp;oldid=765440823\">https:\/\/en.wikipedia.org\/w\/index.php?title=Petroleum&amp;oldid=765440823<\/a><\/span><\/li>\n<li><span style=\"color: #000000;\">Ball, D.W., Hill, J.W., and Scott, R.J.\u00a0(2016) <em>MAP: The Basics of General,\u00a0Organic and Biological\u00a0Chemistry<\/em>.\u00a0 Libre Texts. Available at:<\/span> <span style=\"color: #ff0000;\">https:\/\/chem.libretexts.org\/Textbook_Maps\/Introductory_Chemistry_Textbook_Maps\/Map%3A_The_Basics_of_GOB_Chemistry_(Ball_et_al.)<\/span><\/li>\n<\/ol>\n<\/div>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Chapter 7: Alkanes and Halogenated Hydrocarbons This text is published under creative commons licensing, for referencing and adaptation, please click here. Opening Essay 7.1 Recognition of Organic Structures 7.2 Introduction to Alkanes Straight Chain Alkanes Branched Chain Alkanes Cycloalkanes Classification of Carbon Bonds 7.3 Properties of\u00a0Alkanes Melting Points and Boiling Points Solubility Alkane Properties and [&hellip;]<\/p>\n","protected":false},"author":280,"featured_media":0,"parent":1523,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_seopress_robots_primary_cat":"","_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","_lmt_disableupdate":"","_lmt_disable":"","_et_pb_use_builder":"","_et_pb_old_content":"","_et_gb_content_width":"","footnotes":"","_links_to":"","_links_to_target":""},"class_list":["post-2323","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/wou.edu\/chemistry\/wp-json\/wp\/v2\/pages\/2323","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/wou.edu\/chemistry\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/wou.edu\/chemistry\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/wou.edu\/chemistry\/wp-json\/wp\/v2\/users\/280"}],"replies":[{"embeddable":true,"href":"https:\/\/wou.edu\/chemistry\/wp-json\/wp\/v2\/comments?post=2323"}],"version-history":[{"count":0,"href":"https:\/\/wou.edu\/chemistry\/wp-json\/wp\/v2\/pages\/2323\/revisions"}],"up":[{"embeddable":true,"href":"https:\/\/wou.edu\/chemistry\/wp-json\/wp\/v2\/pages\/1523"}],"wp:attachment":[{"href":"https:\/\/wou.edu\/chemistry\/wp-json\/wp\/v2\/media?parent=2323"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}